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Sagot :
To solve this problem, we need to establish a system of equations that correctly represents the given conditions:
1. The total number of DVDs is 15.
2. The total cost of the DVDs is \[tex]$156. 3. There are two types of DVDs: one type costs \$[/tex]11 each, and the other costs \[tex]$9 each. Let's denote: - \( x \) as the number of \$[/tex]11 DVDs,
- [tex]\( y \)[/tex] as the number of \[tex]$9 DVDs. From the information provided, we can establish the following equations: 1. The total number of DVDs is 15: \[ x + y = 15 \] 2. The total cost of the DVDs is \$[/tex]156. Since each \[tex]$11 DVD contributes \$[/tex]11 to the total cost, and each \[tex]$9 DVD contributes \$[/tex]9 to the total cost, we can write:
[tex]\[ 11x + 9y = 156 \][/tex]
Thus, the correct system of equations to determine [tex]\( x \)[/tex] and [tex]\( y \)[/tex] is:
[tex]\[ \begin{cases} x + y = 15 \\ 11x + 9y = 156 \end{cases} \][/tex]
The answer corresponds to option D:
[tex]\[ x + y = 15 \\ 11x + 9 y=156 \][/tex]
1. The total number of DVDs is 15.
2. The total cost of the DVDs is \[tex]$156. 3. There are two types of DVDs: one type costs \$[/tex]11 each, and the other costs \[tex]$9 each. Let's denote: - \( x \) as the number of \$[/tex]11 DVDs,
- [tex]\( y \)[/tex] as the number of \[tex]$9 DVDs. From the information provided, we can establish the following equations: 1. The total number of DVDs is 15: \[ x + y = 15 \] 2. The total cost of the DVDs is \$[/tex]156. Since each \[tex]$11 DVD contributes \$[/tex]11 to the total cost, and each \[tex]$9 DVD contributes \$[/tex]9 to the total cost, we can write:
[tex]\[ 11x + 9y = 156 \][/tex]
Thus, the correct system of equations to determine [tex]\( x \)[/tex] and [tex]\( y \)[/tex] is:
[tex]\[ \begin{cases} x + y = 15 \\ 11x + 9y = 156 \end{cases} \][/tex]
The answer corresponds to option D:
[tex]\[ x + y = 15 \\ 11x + 9 y=156 \][/tex]
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