Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Color-deficient vision is a sex-linked recessive trait in humans. Parents with the following genotypes have a child:

[tex]\(X^R X^r \times X^r Y\)[/tex]

What is the probability that the child will have color-deficient vision?

A. 0.50
B. 0.25
C. 1.00
D. 0.00


Sagot :

To determine the probability that the child will have color-deficient vision, we need to understand sex-linked inheritance and the given genotypes of the parents.

The mother's genotype is [tex]\(X^R X^r\)[/tex], indicating she has one dominant allele (non-color deficient) and one recessive allele (color deficient). The father's genotype is [tex]\(X^r Y\)[/tex], indicating he has the recessive allele for color deficiency on his X chromosome and does not carry another X chromosome for this trait since he has a Y chromosome.

Let's determine the possible genotypes of their children:

1. Mother's possible alleles: [tex]\(X^R\)[/tex], [tex]\(X^r\)[/tex]
2. Father's possible alleles: [tex]\(X^r\)[/tex], [tex]\(Y\)[/tex]

By combining these, we can form the potential genotypes of the offspring. We have the following combinations and their respective phenotypes:

1. [tex]\(X^R X^r\)[/tex]: This child receives [tex]\(X^R\)[/tex] from the mother and [tex]\(X^r\)[/tex] from the father, resulting in a non-color deficient female.
2. [tex]\(X^R Y\)[/tex]: This child receives [tex]\(X^R\)[/tex] from the mother and [tex]\(Y\)[/tex] from the father, resulting in a non-color deficient male.
3. [tex]\(X^r X^r\)[/tex]: This child receives [tex]\(X^r\)[/tex] from both parents, resulting in a color deficient female.
4. [tex]\(X^r Y\)[/tex]: This child receives [tex]\(X^r\)[/tex] from the mother and [tex]\(Y\)[/tex] from the father, resulting in a color deficient male.

We have four equally likely genotypes for the children. To find the probability of a child being color-deficient, we look at the combinations that result in color deficiency:

- [tex]\(X^r X^r\)[/tex] (color deficient female)
- [tex]\(X^r Y\)[/tex] (color deficient male)

There are 2 combinations that result in color deficiency out of the 4 possible genotypes. Thus, the probability that a child will have color-deficient vision is:

[tex]\[ \frac{\text{Number of color-deficient genotypes}}{\text{Total number of possible genotypes}} = \frac{2}{4} = 0.50 \][/tex]

Therefore, the correct answer is:
A. 0.50
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.