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Given [tex]\( h(t) = -2(t + 5)^2 + 4 \)[/tex], find [tex]\( h(-8) \)[/tex].

Sagot :

GinnyAnswer
Sure, let's find [tex]\( h(-8) \)[/tex] given the function [tex]\( h(t) = -2(t + 5)^2 + 4 \)[/tex].

1. Substitute [tex]\( t = -8 \)[/tex] into the function:

[tex]\[ h(-8) = -2(-8 + 5)^2 + 4 \][/tex]

2. Simplify inside the parentheses:

[tex]\[ -8 + 5 = -3 \][/tex]

So,

[tex]\[ h(-8) = -2(-3)^2 + 4 \][/tex]

3. Square the value inside the parentheses:

[tex]\[ (-3)^2 = 9 \][/tex]

So,

[tex]\[ h(-8) = -2(9) + 4 \][/tex]

4. Multiply with the coefficient:

[tex]\[ -2 \times 9 = -18 \][/tex]

So,

[tex]\[ h(-8) = -18 + 4 \][/tex]

5. Add the final constants:

[tex]\[ -18 + 4 = -14 \][/tex]

Therefore,

[tex]\[ h(-8) = -14 \][/tex]

So, [tex]\( h(-8) = -14 \)[/tex].
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