Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The difference of a number and 6 is the same as 5 times the sum of the number and 2. What is the number?

A. 0
B. -2
C. -1
D. 1


Sagot :

To solve the problem, we need to translate the given statement into a mathematical equation and then solve for the unknown number.

The statement given is:
"The difference of a number and 6 is the same as 5 times the sum of the number and 2."

Let's define the unknown number as [tex]\( x \)[/tex].

1. Translate the statement into an equation:
- The difference of the number and 6 can be written as [tex]\( x - 6 \)[/tex].
- The sum of the number and 2 can be written as [tex]\( x + 2 \)[/tex].
- 5 times the sum of the number and 2 is [tex]\( 5(x + 2) \)[/tex].

Therefore, the equation represents:
[tex]\[ x - 6 = 5(x + 2) \][/tex]

2. Simplify the equation:
To solve for [tex]\( x \)[/tex], we need to simplify and isolate [tex]\( x \)[/tex]:
[tex]\[ x - 6 = 5(x + 2) \][/tex]

3. Distribute the 5 on the right side:
[tex]\[ x - 6 = 5x + 10 \][/tex]

4. Move all terms involving [tex]\( x \)[/tex] to one side:
[tex]\[ x - 5x = 10 + 6 \][/tex]

5. Simplify the equation:
[tex]\[ -4x = 16 \][/tex]

6. Solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{16}{-4} \][/tex]
[tex]\[ x = -4 \][/tex]

So, the number that satisfies the given condition is [tex]\(-4\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{-4} \][/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.