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At an ice cream stand, the purchases for one month are recorded in the table below:

| | Smoothie | Shake | Ice Cream |
|--------------|----------|-------|-----------|
| Strawberry | 41 | 53 | 43 |
| Apple | 73 | 59 | 37 |
| Banana | 89 | 13 | 29 |

If we choose a customer at random, what is the probability that they have purchased a shake or it is strawberry?

[tex]\[ P(\text{Strawberry or Shake}) = \frac{[?]}{\square} \][/tex]

Give your answer in simplest form.


Sagot :

To determine the probability that a randomly chosen customer has purchased either a shake or a strawberry item, we can follow these steps methodically:

1. Collect the total number of purchases:

First, we need to sum all the purchases made:
[tex]\[ \text{Total purchases} = (41 + 73 + 89) + (53 + 59 + 13) + (43 + 37 + 29) \][/tex]
Simplifying within each category:
[tex]\[ = 203 + 125 + 109 = 437 \][/tex]
Thus, the total number of purchases recorded is 437.

2. Calculate the number of strawberry purchases:

The count of strawberry purchases from all categories (Smoothie, Shake, Ice Cream):
[tex]\[ \text{Strawberry purchases} = 41 + 53 + 43 = 137 \][/tex]

3. Calculate the number of shake purchases:

The count of shake purchases from all flavors (Strawberry, Apple, Banana):
[tex]\[ \text{Shake purchases} = 53 + 59 + 13 = 125 \][/tex]

4. Account for the overlap of shake and strawberry purchases:

The count of purchases that are both shake and strawberry:
[tex]\[ \text{Both shake and strawberry purchases} = 53 \][/tex]

5. Use the principle of Inclusion-Exclusion to find the count of either strawberry or shake purchases:

The number of purchases that are either shakes or strawberry:
[tex]\[ \text{Either strawberry or shake} = \text{Strawberry purchases} + \text{Shake purchases} - \text{Both shake and strawberry purchases} \][/tex]
Substituting the values we have:
[tex]\[ = 137 + 125 - 53 = 209 \][/tex]

6. Formulate the probability:

The probability of a randomly chosen customer having purchased either a shake or a strawberry item is the ratio of the number of favorable outcomes (either strawberry or shake) to the total number of outcomes (total purchases):
[tex]\[ P(\text{Strawberry or Shake}) = \frac{\text{Either strawberry or shake}}{\text{Total purchases}} = \frac{209}{437} \][/tex]

So, the probability, expressed in simplest form, is:
[tex]\[ P(\text{Strawberry or Shake}) = \frac{209}{437} \][/tex]