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A triangle has sides measuring 2 inches and 7 inches. If [tex]\( x \)[/tex] represents the length in inches of the third side, which inequality gives the range of possible values for [tex]\( x \)[/tex]?

A. [tex]\( 5 \leq x \leq 9 \)[/tex]
B. [tex]\( 2 \leq x \leq 7 \)[/tex]
C. [tex]\( 5 \ \textless \ x \ \textless \ 9 \)[/tex]
D. [tex]\( 2 \ \textless \ x \ \textless \ 7 \)[/tex]


Sagot :

To determine the range of possible values for the third side [tex]\( x \)[/tex] of a triangle with sides measuring 2 inches and 7 inches, we need to use the triangle inequality theorem. This theorem states:
1. The length of any side of a triangle must be less than the sum of the lengths of the other two sides.
2. The length of any side of a triangle must be greater than the absolute difference of the lengths of the other two sides.

Let’s denote the given sides as [tex]\(a = 2\)[/tex] inches and [tex]\(b = 7\)[/tex] inches. The third side length is denoted as [tex]\(x\)[/tex].

According to the triangle inequality theorem:

1. [tex]\( x \)[/tex] must be greater than the difference of the given sides:
[tex]\[ x > |a - b| \][/tex]
Calculating the absolute difference:
[tex]\[ |2 - 7| = 5 \][/tex]
Therefore:
[tex]\[ x > 5 \][/tex]

2. [tex]\( x \)[/tex] must be less than the sum of the given sides:
[tex]\[ x < a + b \][/tex]
Summing the lengths:
[tex]\[ 2 + 7 = 9 \][/tex]
Therefore:
[tex]\[ x < 9 \][/tex]

Combining these two inequalities, we get:
[tex]\[ 5 < x < 9 \][/tex]

So, the range of possible values for the third side [tex]\( x \)[/tex] is:
[tex]\[ 5 < x < 9 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{C. \ 5 < x < 9} \][/tex]