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Walter is planning a trip to Morocco and needs to adjust his itinerary to stay within a budget of MAD 2,500. The table below shows the cost (in Moroccan dirham, MAD) for each city he is considering:

| City | Cost (MAD) |
|------------|-------------|
| Tangier | 610 |
| Casablanca | 466 |
| Agadir | 950 |
| Rabat | 927 |
| Oujda | 683 |
| Fes | 478 |
| Marrakech | 965 |
| Kenitra | 778 |

Walter's original itinerary includes trips to Marrakech, Fes, Kenitra, and Oujda. He needs to alter his plans to stay within his budget. Which of the following itinerary changes will allow Walter to stay within his budget? (Consider each option individually.)

A. Remove Marrakech
B. Remove Fes
C. Remove Kenitra
D. Remove Oujda

Sagot :

GinnyAnswer
Let's walk through each step of solving the problem.

1. Identify the costs for each city Walter planned to visit:
- Marrakech: MAD 965
- Fes: MAD 478
- Kenitra: MAD 778
- Oujda: MAD 683

2. Calculate the total cost of the original itinerary:
[tex]\( 965 + 478 + 778 + 683 = 2,904 \)[/tex]
The original itinerary costs MAD 2,904, which exceeds Walter’s budget of MAD 2,500.

3. Determine the different itinerary changes to reduce the cost:
- Remove Marrakech:
[tex]\[ 2,904 - 965 = 1,939 \][/tex]
- Remove Fes:
[tex]\[ 2,904 - 478 = 2,426 \][/tex]
- Remove Kenitra:
[tex]\[ 2,904 - 778 = 2,126 \][/tex]
- Remove Oujda:
[tex]\[ 2,904 - 683 = 2,221 \][/tex]
- Remove Marrakech and Fes:
[tex]\[ 2,904 - 965 - 478 = 1,461 \][/tex]
- Remove Marrakech and Kenitra:
[tex]\[ 2,904 - 965 - 778 = 1,161 \][/tex]
- Remove Marrakech and Oujda:
[tex]\[ 2,904 - 965 - 683 = 1,256 \][/tex]
- Remove Fes and Kenitra:
[tex]\[ 2,904 - 478 - 778 = 1,648 \][/tex]
- Remove Fes and Oujda:
[tex]\[ 2,904 - 478 - 683 = 1,743 \][/tex]
- Remove Kenitra and Oujda:
[tex]\[ 2,904 - 778 - 683 = 1,443 \][/tex]

4. Identify which of these changes keep the total cost within the budget of MAD 2,500:
- Remove Marrakech: MAD 1,939
- Remove Fes: MAD 2,426
- Remove Kenitra: MAD 2,126
- Remove Oujda: MAD 2,221
- Remove Marrakech and Fes: MAD 1,461
- Remove Marrakech and Kenitra: MAD 1,161
- Remove Marrakech and Oujda: MAD 1,256
- Remove Fes and Kenitra: MAD 1,648
- Remove Fes and Oujda: MAD 1,743
- Remove Kenitra and Oujda: MAD 1,443

Given these calculations, the possible changes that allow Walter to stay within his budget of MAD 2,500 are:
- Remove Marrakech: MAD 1,939
- Remove Fes: MAD 2,426
- Remove Kenitra: MAD 2,126
- Remove Oujda: MAD 2,221
- Remove Marrakech and Fes: MAD 1,461
- Remove Marrakech and Kenitra: MAD 1,161
- Remove Marrakech and Oujda: MAD 1,256
- Remove Fes and Kenitra: MAD 1,648
- Remove Fes and Oujda: MAD 1,743
- Remove Kenitra and Oujda: MAD 1,443

Thus, each of the listed changes individually would allow Walter to stay within his budget.
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