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A nuclide of [tex]\( \,_{29}^{64}Cu \)[/tex] absorbs a positron. Which is the resulting atom?

A. [tex]\( \,_{29}^{65}Cu \)[/tex]

B. [tex]\( \,_{29}^{63}Cu \)[/tex]

C. [tex]\( \,_{28}^{64}Ni \)[/tex]

D. [tex]\( \,_{30}^{64}Zn \)[/tex]


Sagot :

Let's start by understanding what happens when a nuclide of [tex]\({ }_{29}^{64} Cu\)[/tex] (Copper-64) absorbs a positron.

1. Positron Absorption:
- A positron (essentially the antiparticle of an electron with a positive charge) interacts with a nucleus.
- This interaction converts a proton into a neutron.

2. Impact on the Atomic Number and Mass Number:
- When a proton is converted into a neutron:
- The atomic number decreases by 1 because there is one less proton.
- The mass number remains unchanged because the overall number of nucleons (protons and neutrons) stays the same.

Given:
- The initial atomic number of the atom is 29 (Copper - Cu).
- The initial mass number is 64.

After the positron absorption:
- The atomic number decreases by 1:
[tex]\[ 29 - 1 = 28 \][/tex]
- The mass number remains the same:
[tex]\[ 64 \][/tex]

An element with an atomic number of 28 is Nickel (Ni).

Therefore, the resulting atom after the absorption of a positron by [tex]\({ }_{29}^{64} Cu\)[/tex] is [tex]\({ }_{28}^{64} Ni\)[/tex].

Among the given options:
[tex]\[ \boxed{{ }_{28}^{64} Ni} \][/tex]