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What is the mass of 3.45 moles of [tex]\( NO_2 \)[/tex]?

Molar mass of [tex]\( NO_2 = 46.01 \, g/mol \)[/tex]

[tex]\[ \text{Mass} = \, [?] \, g \, NO_2 \][/tex]

Sagot :

GinnyAnswer
To find the mass of 3.45 moles of [tex]\( \text{NO}_2 \)[/tex], follow these steps:

1. Identify the given values:
- Number of moles ([tex]\( n \)[/tex]) of [tex]\( \text{NO}_2 \)[/tex]: 3.45 moles
- Molar mass ([tex]\( M \)[/tex]) of [tex]\( \text{NO}_2 \)[/tex]: 46.01 g/mol

2. Recall the formula to determine the mass ([tex]\( m \)[/tex]) of a substance when given the moles and the molar mass:
[tex]\[ m = n \times M \][/tex]

3. Substitute the given values into the formula:
[tex]\[ m = 3.45 \, \text{moles} \times 46.01 \, \text{g/mol} \][/tex]

4. Perform the multiplication to find the mass:
[tex]\[ m = 158.7345 \, \text{g} \][/tex]

Therefore, the mass of 3.45 moles of [tex]\( \text{NO}_2 \)[/tex] is 158.7345 grams.
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