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A sample of [tex]\( Ca(C_2H_3O_2)_2 \)[/tex] contains the following:
- [tex]\( 40.08 \, \text{g} \)[/tex] of [tex]\( Ca \)[/tex]
- [tex]\( 48.04 \, \text{g} \)[/tex] of [tex]\( C \)[/tex]
- [tex]\( 6.06 \, \text{g} \)[/tex] of [tex]\( H \)[/tex]
- [tex]\( 64.00 \, \text{g} \)[/tex] of [tex]\( O \)[/tex]

What is the percent composition of [tex]\( O \)[/tex] in the compound?

Sagot :

To determine the percent composition of oxygen in the compound [tex]\( \text{Ca(C}_2\text{H}_3\text{O}_2)_2 \)[/tex], we need to follow these steps:

1. Compute the total mass of the compound:

We have the following masses for each element in the compound:
- Mass of Calcium (Ca): [tex]\( 40.08 \, \text{g} \)[/tex]
- Mass of Carbon (C): [tex]\( 48.04 \, \text{g} \)[/tex]
- Mass of Hydrogen (H): [tex]\( 6.06 \, \text{g} \)[/tex]
- Mass of Oxygen (O): [tex]\( 64.00 \, \text{g} \)[/tex]

The first step is to calculate the total mass of the compound by summing up the masses of all elements:

[tex]\[ \text{Total mass} = \text{Mass of Ca} + \text{Mass of C} + \text{Mass of H} + \text{Mass of O} \][/tex]

Substituting the given values:

[tex]\[ \text{Total mass} = 40.08 \, \text{g} + 48.04 \, \text{g} + 6.06 \, \text{g} + 64.00 \, \text{g} \][/tex]

[tex]\[ \text{Total mass} = 158.18 \, \text{g} \][/tex]

2. Calculate the percent composition of oxygen:

The percent composition of an element in a compound is calculated using the formula:

[tex]\[ \text{Percent composition of an element} = \left( \frac{\text{Mass of the element}}{\text{Total mass of the compound}} \right) \times 100 \][/tex]

Applying this formula for oxygen:

[tex]\[ \text{Percent composition of O} = \left( \frac{\text{Mass of O}}{\text{Total mass}} \right) \times 100 \][/tex]

Substituting the given mass of oxygen and the calculated total mass:

[tex]\[ \text{Percent composition of O} = \left( \frac{64.00 \, \text{g}}{158.18 \, \text{g}} \right) \times 100 \][/tex]

[tex]\[ \text{Percent composition of O} \approx 40.460235175116956 \% \][/tex]

Therefore, the percent composition of oxygen in the compound [tex]\( \text{Ca(C}_2\text{H}_3\text{O}_2)_2 \)[/tex] is approximately [tex]\( 40.46\% \)[/tex].