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While loading, a truck moves 10 meters west from point A to point B in 5 seconds. Then it moves back to point A in 5 seconds.

What are the average speed and average velocity of the truck?

A. Average speed: 2 meters/second, Average velocity: 2 meters/second
B. Average speed: 2 meters/second, Average velocity: 0 meters/second
C. Average speed: 10 meters/second, Average velocity: 10 meters/second
D. Average speed: 0 meters/second, Average velocity: 10 meters/second

Sagot :

Let's break down the problem step-by-step to find the average speed and average velocity of the truck.

### Step 1: Understanding the Journey

1. The truck moves 10 meters west from point A to point B in 5 seconds.
2. Then it returns 10 meters east back to point A in another 5 seconds.

### Step 2: Calculating the Total Distance Traveled

The distance traveled from point A to point B is 10 meters, and the distance from point B back to point A is another 10 meters.

Thus, the total distance traveled is:
[tex]\[ \text{Total distance} = 10 \text{ meters} + 10 \text{ meters} = 20 \text{ meters} \][/tex]

### Step 3: Calculating the Total Time Taken

The time taken to travel from point A to point B is 5 seconds, and the time taken to travel back from point B to point A is another 5 seconds.

Thus, the total time taken is:
[tex]\[ \text{Total time} = 5 \text{ seconds} + 5 \text{ seconds} = 10 \text{ seconds} \][/tex]

### Step 4: Calculating the Average Speed

Average speed is defined as the total distance traveled divided by the total time taken.

[tex]\[ \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{20 \text{ meters}}{10 \text{ seconds}} = 2 \text{ meters/second} \][/tex]

### Step 5: Calculating the Net Displacement

Displacement is a vector quantity that refers to the change in position. Since the truck returns to point A, the net displacement is 0 meters (it ends up at the same point it started).

### Step 6: Calculating the Average Velocity

Average velocity is defined as the total displacement divided by the total time taken.

[tex]\[ \text{Average velocity} = \frac{\text{Net displacement}}{\text{Total time}} = \frac{0 \text{ meters}}{10 \text{ seconds}} = 0 \text{ meters/second} \][/tex]

### Conclusion

The correct answers for this problem are:
- Average speed: 2 meters/second
- Average velocity: 0 meters/second

Hence, the answer to the given question is:

Average speed - 2 meters/second, average velocity - 0 meters/second