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2x - y ≤ 2
Inequality
2x - y ≤ 2
x + 2y ≤ 6
Two Points (x, y) on the Graphed Line Point (x, y) in Shaded Region
(0,
x + 2y ≤ 6
(0,


Sagot :

Answer:

Step-by-step explanation:

It seems like your message got cut off. It looks like you are providing information about a system of inequalities involving \( x \) and \( y \):

1. \( 2x - y \leq 2 \)

2. \( x + 2y \leq 6 \)

These inequalities represent the shaded region in a coordinate plane where the solutions to both inequalities lie.

To find specific points that satisfy these inequalities:

For \( x + 2y \leq 6 \):

- When \( x = 0 \):

 \[ 0 + 2y \leq 6 \]

 \[ 2y \leq 6 \]

 \[ y \leq 3 \]

So, the point \( (0, 3) \) is on the line \( x + 2y = 6 \) and is within the shaded region.

For \( 2x - y \leq 2 \):

- When \( x = 0 \):

 \[ 2(0) - y \leq 2 \]

 \[ -y \leq 2 \]

 \[ y \geq -2 \]

So, the point \( (0, -2) \) is on the line \( 2x - y = 2 \) and is within the shaded region.

Therefore, the points \( (0, 3) \) and \( (0, -2) \) satisfy both inequalities and lie within the shaded region where \( 2x - y \leq 2 \) and \( x + 2y \leq 6 \).

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