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Sagot :
To solve the problem of determining the correct frequency table for plotting a histogram, let's categorize the given data set into suitable intervals. The data set is as follows:
[tex]\[82, 83, 89, 67, 65, 88, 66, 69, 83, 81, 94, 68, 82, 69, 86, 83, 88, 62, 64, 93\][/tex]
Next, we'll allocate these numbers into the intervals:
1. Interval 60-70:
- Numbers: 67, 65, 66, 69, 68, 69, 62, 64
- Count: 8
2. Interval 70-80:
- Numbers: None
- Count: 0
3. Interval 80-90:
- Numbers: 82, 83, 89, 83, 81, 82, 86, 83, 88, 88
- Count: 10
4. Interval 90-100:
- Numbers: 94, 93
- Count: 2
From these counts, we construct the frequency table:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline \text{Interval} & 60-70 & 70-80 & 80-90 & 90-100 \\ \hline \text{Frequency} & 8 & 0 & 10 & 2 \\ \hline \end{tabular} \][/tex]
Hence, Fiona should use the following frequency table for the histogram:
[tex]\[ \text{Option A:} \begin{tabular}{|c|c|c|c|c|} \hline \text{Interval} & 60-70 & 70-80 & 80-90 & 90-100 \\ \hline \text{Frequency} & 8 & 0 & 10 & 2 \\ \hline \end{tabular} \][/tex]
[tex]\[82, 83, 89, 67, 65, 88, 66, 69, 83, 81, 94, 68, 82, 69, 86, 83, 88, 62, 64, 93\][/tex]
Next, we'll allocate these numbers into the intervals:
1. Interval 60-70:
- Numbers: 67, 65, 66, 69, 68, 69, 62, 64
- Count: 8
2. Interval 70-80:
- Numbers: None
- Count: 0
3. Interval 80-90:
- Numbers: 82, 83, 89, 83, 81, 82, 86, 83, 88, 88
- Count: 10
4. Interval 90-100:
- Numbers: 94, 93
- Count: 2
From these counts, we construct the frequency table:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline \text{Interval} & 60-70 & 70-80 & 80-90 & 90-100 \\ \hline \text{Frequency} & 8 & 0 & 10 & 2 \\ \hline \end{tabular} \][/tex]
Hence, Fiona should use the following frequency table for the histogram:
[tex]\[ \text{Option A:} \begin{tabular}{|c|c|c|c|c|} \hline \text{Interval} & 60-70 & 70-80 & 80-90 & 90-100 \\ \hline \text{Frequency} & 8 & 0 & 10 & 2 \\ \hline \end{tabular} \][/tex]
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