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Consider the function [tex][tex]$f(x)=2 \sin 4\left(x-45^{\circ}\right)+1$[/tex][/tex], where [tex][tex]$x$[/tex][/tex] is measured in degrees.

Describe the graph of the function and determine the following:

1. Amplitude
2. Midline equation
3. Range
4. Period
5. Horizontal translation from [tex][tex]$y=\cos (x)$[/tex][/tex]

Justify your answers. (4 marks)


Sagot :

To analyze and describe the given function [tex]\( f(x) = 2 \sin 4 (x - 45^{\circ}) + 1 \)[/tex]:

1. Amplitude:
The amplitude of a trigonometric function [tex]\( a \sin(bx+c) + d \)[/tex] or [tex]\( a \cos(bx+c) + d \)[/tex], is given by the coefficient [tex]\( |a| \)[/tex]. Here, for [tex]\( f(x) = 2 \sin 4 (x - 45^{\circ}) + 1 \)[/tex], [tex]\( a = 2 \)[/tex]. Therefore, the amplitude of the function is:
[tex]\[ \text{Amplitude} = 2 \][/tex]

2. Midline Equation:
The midline of the function is determined by the vertical shift, which is the constant term added to the sine function. Here, the constant term is [tex]\( +1 \)[/tex], so the midline of the function is:
[tex]\[ \text{Midline: } y = 1 \][/tex]

3. Range:
The range of the function is determined by how much the function oscillates above and below the midline. Since the amplitude is 2, the function will reach a maximum value of [tex]\( 1 + 2 = 3 \)[/tex] and a minimum value of [tex]\( 1 - 2 = -1 \)[/tex]. Hence, the range of the function is:
[tex]\[ \text{Range: } [-1, 3] \][/tex]

4. Period:
The period of a sine function [tex]\( a \sin(bx + c) + d \)[/tex] is given by [tex]\( \frac{360^{\circ}}{b} \)[/tex], where [tex]\( b \)[/tex] is the coefficient of [tex]\( x \)[/tex]. Here, [tex]\( b = 4 \)[/tex], so the period of the function is:
[tex]\[ \text{Period: } \frac{360^{\circ}}{4} = 90^{\circ} \][/tex]

5. Horizontal Translation:
The horizontal translation (also known as phase shift) is determined by the expression inside the sine function [tex]\( 4(x - 45^{\circ}) \)[/tex]. The phase shift is given by solving [tex]\( x - \text{Shift} = 0 \)[/tex]. From [tex]\( 4(x - 45^{\circ}) \)[/tex], the shift is [tex]\( +45^{\circ} \)[/tex], indicating a shift to the right by 45 degrees. Hence, the horizontal translation is:
[tex]\[ \text{Horizontal Translation: } 45^{\circ} \text{ to the right} \][/tex]

In summary, for the function [tex]\( f(x) = 2 \sin 4 (x - 45^{\circ}) + 1 \)[/tex]:
- Amplitude: 2
- Midline Equation: [tex]\( y = 1 \)[/tex]
- Range: [tex]\([-1, 3]\)[/tex]
- Period: [tex]\( 90^{\circ} \)[/tex]
- Horizontal Translation: [tex]\( 45^{\circ} \)[/tex] to the right