Sure, let's solve this problem step-by-step.
The question asks which metal, when paired with Silver, would result in no flow of electric charges. To determine this, we need to understand the concept of electrode potential.
1. Definitions and Concept:
- Electrode Potential: This is a measure of the tendency of a metal to gain or lose electrons when in contact with a solution.
- Flow of Electric Charges: When two metals are paired in an electrochemical cell, electric charges will flow from one metal to the other if their electrode potentials are different. The flow happens from the metal with lower potential to the metal with higher potential.
2. Equal Potentials: If two metals have the same electrode potential, there will be no flow of electric charges between them. So, we need to find a metal that has the same electrode potential as Silver.
3. Provided Potentials:
- Magnesium: -2.37 V
- Silver: +0.80 V
- Platinum: +1.20 V
4. Given Options:
- Potassium
- Magnesium
- Silver
- Platinum
5. Since the electrode potential of Silver is +0.80 V, we need to find which metal also has an electrode potential of +0.80 V to result in no flow of electric charges.
6. Reviewing the provided potentials and matching it:
- Magnesium: -2.37 V (not equal to +0.80 V)
- Silver: +0.80 V (this matches our requirement)
- Platinum: +1.20 V (not equal to +0.80 V)
7. The only metal with an electrode potential equal to +0.80 V is Silver itself.
Conclusion: When paired with Silver, the metal that would result in no flow of electric charges is Silver.
