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What is the solution to the inequality [tex][tex]$\frac{d}{7}+4 \leq 0$[/tex][/tex]?

A. [tex][tex]$(-\infty, -28)$[/tex][/tex]
B. [tex][tex]$(-\infty, -28]$[/tex][/tex]
C. [tex][tex]$(28, \infty)$[/tex][/tex]
D. [tex][tex]$[28, \infty)$[/tex][/tex]

Sagot :

To solve the inequality [tex]\(\frac{d}{7} + 4 \leq 0\)[/tex], follow these steps:

1. Isolate the term involving [tex]\(d\)[/tex]:
Start with the inequality:
[tex]\[ \frac{d}{7} + 4 \leq 0 \][/tex]
Subtract 4 from both sides to isolate the fraction:
[tex]\[ \frac{d}{7} \leq -4 \][/tex]

2. Solve for [tex]\(d\)[/tex]:
To eliminate the fraction, multiply both sides of the inequality by 7:
[tex]\[ d \leq -4 \times 7 \][/tex]
Calculate [tex]\(-4 \times 7\)[/tex]:
[tex]\[ d \leq -28 \][/tex]

3. Determine the interval:
The solution to the inequality [tex]\(d \leq -28\)[/tex] includes all values of [tex]\(d\)[/tex] that are less than or equal to [tex]\(-28\)[/tex]. Therefore, the interval notation for the solution is:
[tex]\[ (-\infty, -28] \][/tex]

So, the solution to the inequality [tex]\(\frac{d}{7} + 4 \leq 0\)[/tex] is [tex]\((- \infty, -28]\)[/tex].