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Once a week, you babysit your neighbor's toddler and usually go to a local playground. You notice that each swing on the swing set takes about 3.1 seconds. Use the pendulum formula below to find out how long the swing is. Round your answer to the tenths place.

[tex]\ \textless \ br/\ \textgreater \ T=2 \pi \sqrt{\frac{L}{32}}\ \textless \ br/\ \textgreater \ [/tex]

A. 7.8 feet
B. 49 feet
C. 2 feet
D. 8.7 feet


Sagot :

To determine the length of the swing using the given swing period and the pendulum formula, follow these steps:

1. Identify the given values:
- Period of the swing ([tex]\( T \)[/tex]) = 3.1 seconds
- Acceleration due to gravity ([tex]\( g \)[/tex]) = 32 feet per second squared

2. Recall the pendulum formula:
[tex]\[ T = 2 \pi \sqrt{\frac{L}{g}} \][/tex]

3. Rearrange the formula to solve for [tex]\( L \)[/tex]:
First, isolate the square root by dividing both sides by [tex]\(2\pi\)[/tex]:
[tex]\[ \frac{T}{2\pi} = \sqrt{\frac{L}{g}} \][/tex]

Next, square both sides to get rid of the square root:
[tex]\[ \left(\frac{T}{2\pi}\right)^2 = \frac{L}{g} \][/tex]

Finally, solve for [tex]\( L \)[/tex] by multiplying both sides by [tex]\( g \)[/tex]:
[tex]\[ L = \left(\frac{T}{2\pi}\right)^2 \times g \][/tex]

4. Substitute the known values into the equation:
[tex]\[ L = \left(\frac{3.1}{2\pi}\right)^2 \times 32 \][/tex]

5. Calculate the value step-by-step:
- Calculate [tex]\(2\pi\)[/tex]:
[tex]\[ 2\pi \approx 6.2832 \][/tex]

- Divide [tex]\(T\)[/tex] by [tex]\(2\pi\)[/tex]:
[tex]\[ \frac{3.1}{6.2832} \approx 0.4934 \][/tex]

- Square the result:
[tex]\[ (0.4934)^2 \approx 0.2435 \][/tex]

- Multiply by [tex]\( g \)[/tex] (32):
[tex]\[ 0.2435 \times 32 \approx 7.792 \][/tex]

6. Round the final result to the nearest tenth:
[tex]\[ 7.792 \approx 7.8 \][/tex]

Therefore, the length of the swing is 7.8 feet.

Thus, the correct answer is:

A. 7.8 feet