Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Let's determine which equation models the relationship between the time [tex]\( t \)[/tex] in minutes and the quarts of water [tex]\( w \)[/tex] left in the tub.
From the problem, we know the following:
- The tub initially has 50 quarts of water.
- The tub empties at a rate of 2.5 quarts per minute.
We can use these pieces of information to form a linear equation.
When [tex]\( t = 0 \)[/tex], the initial amount of water [tex]\( w \)[/tex] is 50 quarts. Therefore, we start with the point (0, 50).
For every minute that passes, the water decreases by 2.5 quarts. This tells us the water [tex]\( w \)[/tex] will be impacted by the rate over time.
A linear relationship can be expressed as:
[tex]\[ w = w_{initial} - (rate \times t) \][/tex]
Substituting the given values:
[tex]\[ w = 50 - 2.5t \][/tex]
This equation [tex]\( w = 50 - 2.5t \)[/tex] correctly models the situation.
To find the solution when [tex]\( t = 30 \)[/tex] minutes, we can substitute [tex]\( t \)[/tex] with 30 into our equation:
[tex]\[ w = 50 - 2.5t \][/tex]
Substituting [tex]\( t = 30 \)[/tex]:
[tex]\[ w = 50 - 2.5 \times 30 \][/tex]
[tex]\[ w = 50 - 75 \][/tex]
[tex]\[ w = -25 \][/tex]
Therefore, when [tex]\( t = 30 \)[/tex] minutes, the amount of water left in the tub is [tex]\( -25 \)[/tex] quarts.
So, the correct equation that models the relationship is:
[tex]\[ w = 50 - 2.5t \][/tex]
The solution when the time is 30 minutes is:
[tex]\[ w = -25 \text{ quarts} \][/tex]
From the problem, we know the following:
- The tub initially has 50 quarts of water.
- The tub empties at a rate of 2.5 quarts per minute.
We can use these pieces of information to form a linear equation.
When [tex]\( t = 0 \)[/tex], the initial amount of water [tex]\( w \)[/tex] is 50 quarts. Therefore, we start with the point (0, 50).
For every minute that passes, the water decreases by 2.5 quarts. This tells us the water [tex]\( w \)[/tex] will be impacted by the rate over time.
A linear relationship can be expressed as:
[tex]\[ w = w_{initial} - (rate \times t) \][/tex]
Substituting the given values:
[tex]\[ w = 50 - 2.5t \][/tex]
This equation [tex]\( w = 50 - 2.5t \)[/tex] correctly models the situation.
To find the solution when [tex]\( t = 30 \)[/tex] minutes, we can substitute [tex]\( t \)[/tex] with 30 into our equation:
[tex]\[ w = 50 - 2.5t \][/tex]
Substituting [tex]\( t = 30 \)[/tex]:
[tex]\[ w = 50 - 2.5 \times 30 \][/tex]
[tex]\[ w = 50 - 75 \][/tex]
[tex]\[ w = -25 \][/tex]
Therefore, when [tex]\( t = 30 \)[/tex] minutes, the amount of water left in the tub is [tex]\( -25 \)[/tex] quarts.
So, the correct equation that models the relationship is:
[tex]\[ w = 50 - 2.5t \][/tex]
The solution when the time is 30 minutes is:
[tex]\[ w = -25 \text{ quarts} \][/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.