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What is the range of [tex][tex]$f(x)=\sin(x)$[/tex][/tex]?

A. The set of all real numbers [tex][tex]$-2 \pi \leq y \leq 2 \pi$[/tex][/tex]
B. The set of all real numbers [tex][tex]$-1 \leq y \leq 1$[/tex][/tex]
C. The set of all real numbers [tex][tex]$0 \leq y \leq 2 \pi$[/tex][/tex]
D. The set of all real numbers

Sagot :

To determine the range of the function [tex]\( f(x) = \sin(x) \)[/tex], we need to consider the behavior and output values of the sine function for all real numbers [tex]\( x \)[/tex].

The sine function, [tex]\( \sin(x) \)[/tex], is a periodic function that oscillates between certain values. Specifically, the function takes on values that form a wave pattern, repeating every [tex]\( 2\pi \)[/tex] radians.

Here are the key observations to make:

1. Amplitude: The maximum and minimum values of [tex]\( \sin(x) \)[/tex] are 1 and -1, respectively. This means for any input [tex]\( x \)[/tex], [tex]\( \sin(x) \)[/tex] will always generate output values that lie within this range.

2. Output Values: For [tex]\( \sin(x) \)[/tex], the output values range from -1 to 1 inclusive. It cannot produce values outside this interval.

3. Periodicity: The sine function repeats its values every [tex]\( 2\pi \)[/tex] radians, but this periodicity does not affect the range, only how often the values repeat.

So, the range of the sine function is the set of all [tex]\( y \)[/tex] values such that [tex]\( -1 \leq y \leq 1 \)[/tex].

Therefore, the correct answer is:
[tex]\[ \text{The set of all real numbers } -1 \leq y \leq 1 \][/tex]
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