Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A 2kg body is allowed to roll down an inclined plane 4m long with angle of inclination 30 degree. calculate the work done. Take g as 10m/s square
​

Sagot :

Answer:

Explanation:

We will assume there is no Kinetic energy when the body reaches the bottom of the ramp (since this info was not given)

 Then the work will be equal to the negative  change in Potential Energy (mgh)

m = 2 kg    g = 10 m/s^2     h = 4 sin30  =2 m

mgh = 2 x 10 x 2 = 40 Joules of work

                 the change in potential energy is  

                      -40 J ....then the work is  - -40 = + 40 J

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.