Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To determine the ranking of the objects from most to least dense, we will first calculate the densities of each object using the formula for density:
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
Here are the given values:
- Object [tex]\( W \)[/tex]: Mass [tex]\( = 16 \, \text{g} \)[/tex], Volume [tex]\( = 84 \, \text{cm}^3 \)[/tex]
- Object [tex]\( X \)[/tex]: Mass [tex]\( = 12 \, \text{g} \)[/tex], Volume [tex]\( = 5 \, \text{cm}^3 \)[/tex]
- Object [tex]\( Y \)[/tex]: Mass [tex]\( = 4 \, \text{g} \)[/tex], Volume [tex]\( = 6 \, \text{cm}^3 \)[/tex]
- Object [tex]\( Z \)[/tex]: Mass [tex]\( = 408 \, \text{g} \)[/tex], Volume [tex]\( = 216 \, \text{cm}^3 \)[/tex]
Let's calculate the density for each object:
1. Density of [tex]\( W \)[/tex]:
[tex]\[ \text{Density}_W = \frac{16 \, \text{g}}{84 \, \text{cm}^3} \approx 0.190476 \, \text{g/cm}^3 \][/tex]
2. Density of [tex]\( X \)[/tex]:
[tex]\[ \text{Density}_X = \frac{12 \, \text{g}}{5 \, \text{cm}^3} = 2.4 \, \text{g/cm}^3 \][/tex]
3. Density of [tex]\( Y \)[/tex]:
[tex]\[ \text{Density}_Y = \frac{4 \, \text{g}}{6 \, \text{cm}^3} \approx 0.666667 \, \text{g/cm}^3 \][/tex]
4. Density of [tex]\( Z \)[/tex]:
[tex]\[ \text{Density}_Z = \frac{408 \, \text{g}}{216 \, \text{cm}^3} \approx 1.888889 \, \text{g/cm}^3 \][/tex]
Now, let's rank the objects from most to least dense:
- [tex]\( X \)[/tex]: [tex]\( 2.4 \, \text{g/cm}^3 \)[/tex]
- [tex]\( Z \)[/tex]: [tex]\( \approx 1.888889 \, \text{g/cm}^3 \)[/tex]
- [tex]\( Y \)[/tex]: [tex]\( \approx 0.666667 \, \text{g/cm}^3 \)[/tex]
- [tex]\( W \)[/tex]: [tex]\( \approx 0.190476 \, \text{g/cm}^3 \)[/tex]
Thus, the correct ranking of objects from most to least dense is:
[tex]\[ X, Z, Y, W \][/tex]
So, the correct answer is:
[tex]\[ \boxed{X, Z, Y, W} \][/tex]
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
Here are the given values:
- Object [tex]\( W \)[/tex]: Mass [tex]\( = 16 \, \text{g} \)[/tex], Volume [tex]\( = 84 \, \text{cm}^3 \)[/tex]
- Object [tex]\( X \)[/tex]: Mass [tex]\( = 12 \, \text{g} \)[/tex], Volume [tex]\( = 5 \, \text{cm}^3 \)[/tex]
- Object [tex]\( Y \)[/tex]: Mass [tex]\( = 4 \, \text{g} \)[/tex], Volume [tex]\( = 6 \, \text{cm}^3 \)[/tex]
- Object [tex]\( Z \)[/tex]: Mass [tex]\( = 408 \, \text{g} \)[/tex], Volume [tex]\( = 216 \, \text{cm}^3 \)[/tex]
Let's calculate the density for each object:
1. Density of [tex]\( W \)[/tex]:
[tex]\[ \text{Density}_W = \frac{16 \, \text{g}}{84 \, \text{cm}^3} \approx 0.190476 \, \text{g/cm}^3 \][/tex]
2. Density of [tex]\( X \)[/tex]:
[tex]\[ \text{Density}_X = \frac{12 \, \text{g}}{5 \, \text{cm}^3} = 2.4 \, \text{g/cm}^3 \][/tex]
3. Density of [tex]\( Y \)[/tex]:
[tex]\[ \text{Density}_Y = \frac{4 \, \text{g}}{6 \, \text{cm}^3} \approx 0.666667 \, \text{g/cm}^3 \][/tex]
4. Density of [tex]\( Z \)[/tex]:
[tex]\[ \text{Density}_Z = \frac{408 \, \text{g}}{216 \, \text{cm}^3} \approx 1.888889 \, \text{g/cm}^3 \][/tex]
Now, let's rank the objects from most to least dense:
- [tex]\( X \)[/tex]: [tex]\( 2.4 \, \text{g/cm}^3 \)[/tex]
- [tex]\( Z \)[/tex]: [tex]\( \approx 1.888889 \, \text{g/cm}^3 \)[/tex]
- [tex]\( Y \)[/tex]: [tex]\( \approx 0.666667 \, \text{g/cm}^3 \)[/tex]
- [tex]\( W \)[/tex]: [tex]\( \approx 0.190476 \, \text{g/cm}^3 \)[/tex]
Thus, the correct ranking of objects from most to least dense is:
[tex]\[ X, Z, Y, W \][/tex]
So, the correct answer is:
[tex]\[ \boxed{X, Z, Y, W} \][/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.