Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A ball is thrown downward with an initial velocity of 15 m/s. Using the approximate value of g = 10 m/s². Calculate the velocity of the ball 3.2 seconds after it is released.

Sagot :

Answer:47m/sec

Explanation:

To solve this problem, we can use the kinematic equation that relates the final velocity (vv), initial velocity (uu), acceleration due to gravity (gg), and time (tt):

v=u+gt

Given:

   Initial velocity, u=15u=15 m/s (downward)

   Acceleration due to gravity, g=10g=10 m/s22 (downward)

   Time, t=3.2t=3.2 seconds

Now, substitute these values into the equation:

v=15 m/s+(10 m/s2)(3.2 s)v=15m/s+(10m/s2)(3.2s)

Calculate the right-hand side:

v=15 m/s+32 m/sv=15m/s+32m/s

v=47 m/sv=47m/s

Therefore, the velocity of the ball 3.2 seconds after it is released is 47 m/s47m/s​ downward.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.