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For what values of [tex][tex]$x$[/tex][/tex] is the rational expression below undefined? Check all that apply.

[tex]$
\frac{x-7}{2x^2-32}
$[/tex]

A. -2
B. 7
C. 4
D. -4
E. -7
F. 2

Sagot :

To determine for which values of [tex]\( x \)[/tex] the rational expression

[tex]\[ \frac{x-7}{2x^2 - 32} \][/tex]

is undefined, we need to identify the values of [tex]\( x \)[/tex] that make the denominator equal to zero.

Start by setting the denominator equal to zero and solving for [tex]\( x \)[/tex]:

[tex]\[ 2x^2 - 32 = 0 \][/tex]

First, add 32 to both sides of the equation:

[tex]\[ 2x^2 = 32 \][/tex]

Next, divide both sides of the equation by 2:

[tex]\[ x^2 = 16 \][/tex]

To solve for [tex]\( x \)[/tex], take the square root of both sides:

[tex]\[ x = \pm 4 \][/tex]

This means [tex]\( x = 4 \)[/tex] and [tex]\( x = -4 \)[/tex] are the values for which the denominator is zero and thus, the rational expression is undefined.

Among the given options:
- A. [tex]\(-2\)[/tex]
- B. [tex]\(7\)[/tex]
- C. [tex]\(4\)[/tex]
- D. [tex]\(-4\)[/tex]
- E. [tex]\(-7\)[/tex]
- F. [tex]\(2\)[/tex]

The correct values that make the rational expression undefined are [tex]\( x = 4 \)[/tex] and [tex]\( x = -4 \)[/tex].

Therefore, the correct answers are:
- C. [tex]\(4\)[/tex]
- D. [tex]\(-4\)[/tex]