Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To determine the values of [tex]\( x \)[/tex] for which the rational expression
[tex]\[ \frac{x+8}{x^2 - 2x - 24} \][/tex]
is undefined, we need to focus on the denominator. A rational expression is undefined whenever its denominator is equal to zero because division by zero is undefined.
Let's find the values of [tex]\( x \)[/tex] that make the denominator zero. Consider the denominator [tex]\( x^2 - 2x - 24 \)[/tex]. We set it equal to zero and solve for [tex]\( x \)[/tex]:
[tex]\[ x^2 - 2x - 24 = 0 \][/tex]
To solve this quadratic equation, we can factor it. We need to find two numbers that multiply to [tex]\(-24\)[/tex] (the constant term) and add to [tex]\(-2\)[/tex] (the coefficient of the middle term). These two numbers are [tex]\(-6\)[/tex] and [tex]\(4\)[/tex]. So, we factor the quadratic expression:
[tex]\[ x^2 - 2x - 24 = (x - 6)(x + 4) \][/tex]
Thus, we rewrite the equation as:
[tex]\[ (x - 6)(x + 4) = 0 \][/tex]
To find the values of [tex]\( x \)[/tex] that satisfy this equation, we set each factor equal to zero:
[tex]\[ x - 6 = 0 \quad \text{or} \quad x + 4 = 0 \][/tex]
Solving these simple linear equations, we get:
[tex]\[ x = 6 \quad \text{or} \quad x = -4 \][/tex]
Hence, the rational expression is undefined for [tex]\( x = 6 \)[/tex] and [tex]\( x = -4 \)[/tex].
Therefore, the correct answers are:
A. -4
B. 6
[tex]\[ \frac{x+8}{x^2 - 2x - 24} \][/tex]
is undefined, we need to focus on the denominator. A rational expression is undefined whenever its denominator is equal to zero because division by zero is undefined.
Let's find the values of [tex]\( x \)[/tex] that make the denominator zero. Consider the denominator [tex]\( x^2 - 2x - 24 \)[/tex]. We set it equal to zero and solve for [tex]\( x \)[/tex]:
[tex]\[ x^2 - 2x - 24 = 0 \][/tex]
To solve this quadratic equation, we can factor it. We need to find two numbers that multiply to [tex]\(-24\)[/tex] (the constant term) and add to [tex]\(-2\)[/tex] (the coefficient of the middle term). These two numbers are [tex]\(-6\)[/tex] and [tex]\(4\)[/tex]. So, we factor the quadratic expression:
[tex]\[ x^2 - 2x - 24 = (x - 6)(x + 4) \][/tex]
Thus, we rewrite the equation as:
[tex]\[ (x - 6)(x + 4) = 0 \][/tex]
To find the values of [tex]\( x \)[/tex] that satisfy this equation, we set each factor equal to zero:
[tex]\[ x - 6 = 0 \quad \text{or} \quad x + 4 = 0 \][/tex]
Solving these simple linear equations, we get:
[tex]\[ x = 6 \quad \text{or} \quad x = -4 \][/tex]
Hence, the rational expression is undefined for [tex]\( x = 6 \)[/tex] and [tex]\( x = -4 \)[/tex].
Therefore, the correct answers are:
A. -4
B. 6
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.