Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine the vertex of the quadratic function [tex]\( f(x) = x^2 - 18x + 60 \)[/tex], we can follow these steps:
### Step 1: Finding the [tex]\( x \)[/tex]-coordinate of the vertex
The [tex]\( x \)[/tex]-coordinate of the vertex for a quadratic function of the form [tex]\( ax^2 + bx + c \)[/tex] can be found using the formula:
[tex]\[ x = -\frac{b}{2a} \][/tex]
For the given function:
[tex]\[ a = 1 \][/tex]
[tex]\[ b = -18 \][/tex]
[tex]\[ c = 60 \][/tex]
Plugging in the values, we get:
[tex]\[ x = -\frac{-18}{2 \times 1} \][/tex]
[tex]\[ x = \frac{18}{2} \][/tex]
[tex]\[ x = 9 \][/tex]
### Step 2: Finding the [tex]\( y \)[/tex]-coordinate of the vertex
To find the [tex]\( y \)[/tex]-coordinate of the vertex, we substitute [tex]\( x = 9 \)[/tex] back into the function:
[tex]\[ y = f(9) = 9^2 - 18 \times 9 + 60 \][/tex]
[tex]\[ y = 81 - 162 + 60 \][/tex]
[tex]\[ y = 81 - 162 + 60 \][/tex]
[tex]\[ y = -21 \][/tex]
So, the vertex of the function is at [tex]\( (9, -21) \)[/tex].
### Step 3: Analyzing the given statements
Let's evaluate each statement based on our calculations:
1. The [tex]\( x \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-coordinate.
- Here, [tex]\( x = 9 \)[/tex] and [tex]\( y = -21 \)[/tex].
- Since [tex]\( 9 \)[/tex] is greater than [tex]\( -21 \)[/tex], this statement is true.
2. The [tex]\( x \)[/tex]-coordinate of the vertex is negative.
- The [tex]\( x \)[/tex]-coordinate is [tex]\( 9 \)[/tex], which is not negative. Therefore, this statement is false.
3. The [tex]\( y \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-intercept.
- The [tex]\( y \)[/tex]-intercept is the [tex]\( y \)[/tex]-value when [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 0^2 - 18 \times 0 + 60 = 60 \][/tex]
- The [tex]\( y \)[/tex]-coordinate of the vertex is [tex]\( -21 \)[/tex], which is not greater than [tex]\( 60 \)[/tex]. Therefore, this statement is false.
4. The [tex]\( y \)[/tex]-coordinate of the vertex is positive.
- The [tex]\( y \)[/tex]-coordinate is [tex]\( -21 \)[/tex], which is not positive. Therefore, this statement is false.
### Conclusion
The statement about the vertex of the function that is true is:
- The [tex]\( x \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-coordinate.
### Step 1: Finding the [tex]\( x \)[/tex]-coordinate of the vertex
The [tex]\( x \)[/tex]-coordinate of the vertex for a quadratic function of the form [tex]\( ax^2 + bx + c \)[/tex] can be found using the formula:
[tex]\[ x = -\frac{b}{2a} \][/tex]
For the given function:
[tex]\[ a = 1 \][/tex]
[tex]\[ b = -18 \][/tex]
[tex]\[ c = 60 \][/tex]
Plugging in the values, we get:
[tex]\[ x = -\frac{-18}{2 \times 1} \][/tex]
[tex]\[ x = \frac{18}{2} \][/tex]
[tex]\[ x = 9 \][/tex]
### Step 2: Finding the [tex]\( y \)[/tex]-coordinate of the vertex
To find the [tex]\( y \)[/tex]-coordinate of the vertex, we substitute [tex]\( x = 9 \)[/tex] back into the function:
[tex]\[ y = f(9) = 9^2 - 18 \times 9 + 60 \][/tex]
[tex]\[ y = 81 - 162 + 60 \][/tex]
[tex]\[ y = 81 - 162 + 60 \][/tex]
[tex]\[ y = -21 \][/tex]
So, the vertex of the function is at [tex]\( (9, -21) \)[/tex].
### Step 3: Analyzing the given statements
Let's evaluate each statement based on our calculations:
1. The [tex]\( x \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-coordinate.
- Here, [tex]\( x = 9 \)[/tex] and [tex]\( y = -21 \)[/tex].
- Since [tex]\( 9 \)[/tex] is greater than [tex]\( -21 \)[/tex], this statement is true.
2. The [tex]\( x \)[/tex]-coordinate of the vertex is negative.
- The [tex]\( x \)[/tex]-coordinate is [tex]\( 9 \)[/tex], which is not negative. Therefore, this statement is false.
3. The [tex]\( y \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-intercept.
- The [tex]\( y \)[/tex]-intercept is the [tex]\( y \)[/tex]-value when [tex]\( x = 0 \)[/tex]:
[tex]\[ f(0) = 0^2 - 18 \times 0 + 60 = 60 \][/tex]
- The [tex]\( y \)[/tex]-coordinate of the vertex is [tex]\( -21 \)[/tex], which is not greater than [tex]\( 60 \)[/tex]. Therefore, this statement is false.
4. The [tex]\( y \)[/tex]-coordinate of the vertex is positive.
- The [tex]\( y \)[/tex]-coordinate is [tex]\( -21 \)[/tex], which is not positive. Therefore, this statement is false.
### Conclusion
The statement about the vertex of the function that is true is:
- The [tex]\( x \)[/tex]-coordinate of the vertex is greater than the [tex]\( y \)[/tex]-coordinate.
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.