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Jimmy is a tutor in the science club. He charges [tex][tex]$\$[/tex]40[tex]$[/tex] per semester to privately tutor other students and an additional [tex]$[/tex]\[tex]$10$[/tex][/tex] for home visits to help him pay for gas. If Jimmy made less than [tex][tex]$\$[/tex]80$[/tex] this semester for tutoring 1 student, which inequality can be used to determine how many times he visited the student's home?

A. [tex]50x \ \textless \ 80[/tex]
B. [tex]40 + 10x \ \textless \ 80[/tex]
C. [tex]\frac{x}{10} + 40 \ \textless \ 80[/tex]
D. [tex]40x + 10 \ \textless \ 80[/tex]


Sagot :

Let's break down the problem step by step to find the correct inequality to determine how many times Jimmy visited the student's home.

1. Identify the Fixed and Variable Charges:
- Jimmy charges a fixed amount of \[tex]$40 per semester for tutoring. - In addition to the fixed charge, he charges an extra \$[/tex]10 for each home visit. Let [tex]\( x \)[/tex] represent the number of home visits.

2. Establish the Total Earnings:
- The total amount Jimmy earns from tutoring one student would be the sum of the fixed semester charge and the additional charge for home visits.
- Hence, the total earnings can be represented by the expression: [tex]\( 40 + 10x \)[/tex].

3. Set Up the Inequality:
- Jimmy made less than \[tex]$80 this semester from tutoring one student. - So, the total earnings should be less than \$[/tex]80.

4. Formulate the Inequality:
- The inequality to represent this situation is: [tex]\( 40 + 10x < 80 \)[/tex].

Therefore, the correct inequality to determine how many times Jimmy visited the student's home is:

B. [tex]\( 40 + 10x < 80 \)[/tex]

Based on the detailed breakdown, this inequality correctly represents the scenario described in the problem.
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