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Sagot :
Absolutely, let's delve into the problem step by step.
We are given:
1. The number of waves passing per second (wave count): 10 waves
2. The speed of the waves: 5 meters per second (m/s)
To find the wavelength, we can use the relationship between speed, frequency, and wavelength of a wave, which is given by the formula:
[tex]\[ \text{Speed of the wave} = \text{Frequency} \times \text{Wavelength} \][/tex]
First, we need to identify the frequency. Frequency ([tex]\(f\)[/tex]) is defined as the number of waves passing a point per second. Here, the wave count is 10 waves, so:
[tex]\[ \text{Frequency} = 10 \, \text{Hz} \][/tex]
We need to isolate the wavelength ([tex]\( \lambda \)[/tex]) in the formula:
[tex]\[ \lambda = \frac{\text{Speed}}{\text{Frequency}} \][/tex]
Plugging the given values into the rearranged formula:
[tex]\[ \lambda = \frac{5 \, \text{m/s}}{10 \, \text{Hz}} \][/tex]
[tex]\[ \lambda = 0.5 \, \text{meters} \][/tex]
Therefore, the wavelength is [tex]\(0.5\)[/tex] meters.
We are given:
1. The number of waves passing per second (wave count): 10 waves
2. The speed of the waves: 5 meters per second (m/s)
To find the wavelength, we can use the relationship between speed, frequency, and wavelength of a wave, which is given by the formula:
[tex]\[ \text{Speed of the wave} = \text{Frequency} \times \text{Wavelength} \][/tex]
First, we need to identify the frequency. Frequency ([tex]\(f\)[/tex]) is defined as the number of waves passing a point per second. Here, the wave count is 10 waves, so:
[tex]\[ \text{Frequency} = 10 \, \text{Hz} \][/tex]
We need to isolate the wavelength ([tex]\( \lambda \)[/tex]) in the formula:
[tex]\[ \lambda = \frac{\text{Speed}}{\text{Frequency}} \][/tex]
Plugging the given values into the rearranged formula:
[tex]\[ \lambda = \frac{5 \, \text{m/s}}{10 \, \text{Hz}} \][/tex]
[tex]\[ \lambda = 0.5 \, \text{meters} \][/tex]
Therefore, the wavelength is [tex]\(0.5\)[/tex] meters.
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