Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine the cost of each ticket for the air show that Joel bought, you should follow these steps:
1. Identify the total number of tickets purchased: Joel bought 6 tickets.
2. Identify the total amount spent on the tickets: Joel spent [tex]$156 in total. 3. Calculate the cost per ticket: To find the cost of each ticket, you need to divide the total cost by the number of tickets. Here is the step-by-step calculation: \[ \text{Cost per ticket} = \frac{\text{Total cost}}{\text{Number of tickets}} \] Substitute the given values: \[ \text{Cost per ticket} = \frac{156}{6} \] 4. Perform the division: \[ \text{Cost per ticket} = 26.0 \] Therefore, each ticket cost $[/tex]26.00.
So, the cost of each ticket Joel bought is $26.00.
1. Identify the total number of tickets purchased: Joel bought 6 tickets.
2. Identify the total amount spent on the tickets: Joel spent [tex]$156 in total. 3. Calculate the cost per ticket: To find the cost of each ticket, you need to divide the total cost by the number of tickets. Here is the step-by-step calculation: \[ \text{Cost per ticket} = \frac{\text{Total cost}}{\text{Number of tickets}} \] Substitute the given values: \[ \text{Cost per ticket} = \frac{156}{6} \] 4. Perform the division: \[ \text{Cost per ticket} = 26.0 \] Therefore, each ticket cost $[/tex]26.00.
So, the cost of each ticket Joel bought is $26.00.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.