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An atom of which element bonds with an atom of hydrogen to form the most polar bond?

1. Bromine [tex][tex]$Br \cdot H$[/tex][/tex]
2. Chlorine [tex][tex]$Cl \cdot H$[/tex][/tex]
3. Fluorine [tex][tex]$F \cdot H$[/tex][/tex]
4. Iodine [tex][tex]$I \cdot H$[/tex][/tex]

Sagot :

GinnyAnswer
To determine which element forms the most polar bond with hydrogen, we need to consider the concept of electronegativity. Electronegativity is the tendency of an atom to attract a bonding pair of electrons. The greater the difference in electronegativity between the bonded atoms, the more polar the bond will be.

Given the elements in the options:

1. Bromine
2. Chlorine
3. Fluorine
4. Iodine

Let's analyze these elements based on their electronegativities:
- Bromine: 2.96
- Chlorine: 3.16
- Fluorine: 3.98
- Iodine: 2.66

Since we are considering the bond's polarity, the most polar bond will be formed between hydrogen and the element with the highest electronegativity.

Among the given elements, fluorine has the highest electronegativity (3.98). Therefore, the bond between hydrogen and fluorine will be the most polar.

Hence, the answer is:
(3) fluorine
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