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Sagot :
Let's complete the table by placing each quantity in the correct location based on the bond type:
The bond types are [tex]\(N - N\)[/tex], [tex]\(N = N\)[/tex], and [tex]\(N \equiv N\)[/tex].
1. For [tex]\(N - N\)[/tex] (single bond):
- Bond Energy: 167 kJ/mol
- Bond Length: 125 pm
2. For [tex]\(N = N\)[/tex] (double bond):
- Bond Energy: 418 kJ/mol
- Bond Length: 145 pm
3. For [tex]\(N \equiv N\)[/tex] (triple bond):
- Bond Energy: 942 kJ/mol
- Bond Length: 110 pm
Now, let's fill in the table:
[tex]\[ \begin{array}{|c|l|l|} \hline & \text{Bond Energy} & \text{Bond Length} \\ \hline N - N & 167 \, \text{kJ/mol} & 125 \, \text{pm} \\ \hline N = N & 418 \, \text{kJ/mol} & 145 \, \text{pm} \\ \hline N \equiv N & 942 \, \text{kJ/mol} & 110 \, \text{pm} \\ \hline \end{array} \][/tex]
This completes the table with the correct bond energies and bond lengths.
The bond types are [tex]\(N - N\)[/tex], [tex]\(N = N\)[/tex], and [tex]\(N \equiv N\)[/tex].
1. For [tex]\(N - N\)[/tex] (single bond):
- Bond Energy: 167 kJ/mol
- Bond Length: 125 pm
2. For [tex]\(N = N\)[/tex] (double bond):
- Bond Energy: 418 kJ/mol
- Bond Length: 145 pm
3. For [tex]\(N \equiv N\)[/tex] (triple bond):
- Bond Energy: 942 kJ/mol
- Bond Length: 110 pm
Now, let's fill in the table:
[tex]\[ \begin{array}{|c|l|l|} \hline & \text{Bond Energy} & \text{Bond Length} \\ \hline N - N & 167 \, \text{kJ/mol} & 125 \, \text{pm} \\ \hline N = N & 418 \, \text{kJ/mol} & 145 \, \text{pm} \\ \hline N \equiv N & 942 \, \text{kJ/mol} & 110 \, \text{pm} \\ \hline \end{array} \][/tex]
This completes the table with the correct bond energies and bond lengths.
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