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\begin{tabular}{|c|c|}
\hline Year & Precipitation (inches) \\
\hline 2005 & 5.98 \\
\hline 2006 & 6.05 \\
\hline 2007 & 7.59 \\
\hline 2008 & 5.27 \\
\hline 2009 & 3.11 \\
\hline 2010 & 7.18 \\
\hline 2011 & 2.95 \\
\hline 2012 & 7.22 \\
\hline 2013 & 2.61 \\
\hline
\end{tabular}

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013. What was the mean amount of precipitation during this time? Round to the nearest hundredth.

A. 1.97 inches
B. 2.61 inches
C. 5.33 inches
D. 5.98 inches


Sagot :

To determine the mean amount of precipitation in December for Washington state from 2005 to 2013, follow these steps:

1. List the precipitation data for each year:
5.98, 6.05, 7.59, 5.27, 3.11, 7.18, 2.95, 7.22, 2.61

2. Calculate the total precipitation by summing all the values:
[tex]\[ 5.98 + 6.05 + 7.59 + 5.27 + 3.11 + 7.18 + 2.95 + 7.22 + 2.61 = 47.96 \][/tex]

3. Count the number of years:
The number of values (or years) is 9.

4. Find the mean by dividing the total precipitation by the number of years:
[tex]\[ \frac{47.96}{9} = 5.328888888888889 \][/tex]

5. Round the mean to the nearest hundredth:
[tex]\[ 5.328888888888889 \approx 5.33 \][/tex]

Therefore, the mean amount of precipitation during this time, rounded to the nearest hundredth, is 5.33 inches.

The correct answer is:
[tex]\[ \boxed{5.33 \text{ inches}} \][/tex]