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Cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (BbEe).

1. First, draw a Punnett square in your notes.
2. For each offspring in the Punnett square, determine the phenotype (i.e., fur color and eye color).
3. Finally, use that information to fill in the predicted fraction of each phenotype in the data table below.

\begin{tabular}{|l|c|c|c|c|}
\hline
& \begin{tabular}{c}
Black \\
Fur and \\
Black \\
Eyes
\end{tabular}
& \begin{tabular}{c}
Black \\
Fur and \\
Red \\
Eyes
\end{tabular}
& \begin{tabular}{c}
White \\
Fur and \\
Black \\
Eyes
\end{tabular}
& \begin{tabular}{c}
White \\
Fur and \\
Red \\
Eyes
\end{tabular} \\
\hline
\begin{tabular}{c}
Predicted \\
Fraction
\end{tabular}
& [tex]$\square / 16$[/tex]
& [tex]$\square / 16$[/tex]
& [tex]$\square / 16$[/tex]
& [tex]$\square / 16$[/tex] \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
To solve this problem, we need to analyze the genetic cross between a parent that is homozygous recessive for both traits (bbee) and a dihybrid parent (BbEe). Let's break down the process into clear steps.

1. Identify Gametes:
- For the homozygous recessive parent (bbee), we only have one type of gamete: `be`.
- For the dihybrid parent (BbEe), the possible gametes are: `BE`, `Be`, `bE`, and `be`.

2. Construct the Punnett Square:
- We will combine the gametes from each parent to form the offspring genotypes.
- The Punnett Square will represent all possible combinations.

3. Determine Offspring Genotypes:
- Combine each gamete from the homozygous recessive parent with each gamete from the dihybrid parent.

| | BE | Be | bE | be |
|-----------|------|------|------|------|
| be | BbEe | Bbee | bbEe | bbee |

4. Determine Phenotypes:
- The phenotypes are based on the dominant and recessive alleles:
- Fur Color: Dominant B = Black Fur, Recessive b = White Fur
- Eye Color: Dominant E = Black Eyes, Recessive e = Red Eyes

- For each genotype:
- `BbEe`: Black Fur and Black Eyes (dominant B and E)
- `Bbee`: Black Fur and Red Eyes (dominant B and recessive e)
- `bbEe`: White Fur and Black Eyes (recessive b and dominant E)
- `bbee`: White Fur and Red Eyes (recessive b and e)

5. Count Phenotypes:
- We have a total of four different phenotypes and each combination is equally likely.

6. Predicted Fractions:
- Each phenotype occurs 1 out of 4 times in the Punnett Square, representing 1/4 of the total.

Therefore, the table of predicted fractions of each phenotype filled in is:

[tex]\[ \begin{tabular}{|l|c|c|c|c|} \hline & \begin{tabular}{c} Black \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} Black \\ Fur and \\ Red \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Red \\ Eyes \end{tabular} \\ \hline \begin{tabular}{c} Predicted \\ Fraction \end{tabular} & $\frac{1}{4}$ & $\frac{1}{4}$ & $\frac{1}{4}$ & $\frac{1}{4}$ \\ \hline \end{tabular} \][/tex]
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