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Sagot :
Let's break down the given real-world scenario into a system of inequalities step by step:
1. Constraints Based on Room Capacity:
- The total number of people (adults and campers) that can be accommodated in the room is 200. Therefore, the sum of the number of adults [tex]\( x \)[/tex] and the number of campers [tex]\( y \)[/tex] should be less than or equal to 200.
This can be represented as:
[tex]\[ x + y \leq 200 \][/tex]
2. Constraints Based on Budget:
- The cost for each adult is [tex]$4, and the cost for each camper is $[/tex]3. The total budget for the event is [tex]$750. Therefore, the overall cost for the number of adults \( x \) and the number of campers \( y \) should be less than or equal to $[/tex]750.
This can be represented as:
[tex]\[ 4x + 3y \leq 750 \][/tex]
Putting these constraints together, the system of inequalities for this scenario can be written as:
[tex]\[ \begin{cases} x + y \leq 200 & \text{(Total number of people)} \\ 4x + 3y \leq 750 & \text{(Total cost within budget)} \end{cases} \][/tex]
So, the correct system of inequalities is:
[tex]\[ \begin{array}{r} x + y \leq 200 \\ 4 x + 3 y \leq 750 \end{array} \][/tex]
The correct option is:
[tex]\[ \begin{array}{r} x + y \leq 200 \\ 4 x + 3 y \leq 750 \end{array} \][/tex]
1. Constraints Based on Room Capacity:
- The total number of people (adults and campers) that can be accommodated in the room is 200. Therefore, the sum of the number of adults [tex]\( x \)[/tex] and the number of campers [tex]\( y \)[/tex] should be less than or equal to 200.
This can be represented as:
[tex]\[ x + y \leq 200 \][/tex]
2. Constraints Based on Budget:
- The cost for each adult is [tex]$4, and the cost for each camper is $[/tex]3. The total budget for the event is [tex]$750. Therefore, the overall cost for the number of adults \( x \) and the number of campers \( y \) should be less than or equal to $[/tex]750.
This can be represented as:
[tex]\[ 4x + 3y \leq 750 \][/tex]
Putting these constraints together, the system of inequalities for this scenario can be written as:
[tex]\[ \begin{cases} x + y \leq 200 & \text{(Total number of people)} \\ 4x + 3y \leq 750 & \text{(Total cost within budget)} \end{cases} \][/tex]
So, the correct system of inequalities is:
[tex]\[ \begin{array}{r} x + y \leq 200 \\ 4 x + 3 y \leq 750 \end{array} \][/tex]
The correct option is:
[tex]\[ \begin{array}{r} x + y \leq 200 \\ 4 x + 3 y \leq 750 \end{array} \][/tex]
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