Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let's evaluate each of the given statements one by one based on the conditions provided: integer [tex]\( k \)[/tex] is negative and integer [tex]\( c \)[/tex] is the square of a positive integer less than 10.
Step-by-Step Solution:
1. Analyze Statement A: [tex]\( k^2 \geq c \)[/tex]
Here, we need to determine whether the square of [tex]\( k \)[/tex] (which is negative) is greater than or equal to [tex]\( c \)[/tex] (which is a positive integer less than 100).
Given the result, [tex]\( k^2 \geq c \)[/tex] is False.
2. Analyze Statement B: [tex]\( c - k \leq 0 \)[/tex]
We need to determine whether [tex]\( c - k \leq 0 \)[/tex]. Since [tex]\( k \)[/tex] is negative and [tex]\( c \)[/tex] is positive, subtracting [tex]\( k \)[/tex] (a negative number) from [tex]\( c \)[/tex] (a positive number) essentially adds to [tex]\( c \)[/tex]:
[tex]\[ c - k = c + |k| > c \][/tex]
Given the result, [tex]\( c - k \leq 0 \)[/tex] is False.
3. Analyze Statement C: [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex]
This statement examines whether the square of the product of [tex]\( k \)[/tex] and [tex]\( c \)[/tex] is greater than or equal to the square root of [tex]\( c \)[/tex]:
[tex]\[ (k c)^2 = (k^2 \cdot c^2) \geq \sqrt{c} \][/tex]
Given the result, [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex] is True.
4. Analyze Statement D: [tex]\( k^2 \leq c^2 \)[/tex]
This statement evaluates if the square of [tex]\( k \)[/tex] is less than or equal to the square of [tex]\( c \)[/tex]:
[tex]\[ k^2 \leq c^2 \][/tex]
Given the result, [tex]\( k^2 \leq c^2 \)[/tex] is True.
Therefore, based on the analysis:
- Statement A is false.
- Statement B is false.
- Statement C is true.
- Statement D is true.
Conclusion:
The statements that must be true are:
- [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex]
- [tex]\( k^2 \leq c^2 \)[/tex]
Step-by-Step Solution:
1. Analyze Statement A: [tex]\( k^2 \geq c \)[/tex]
Here, we need to determine whether the square of [tex]\( k \)[/tex] (which is negative) is greater than or equal to [tex]\( c \)[/tex] (which is a positive integer less than 100).
Given the result, [tex]\( k^2 \geq c \)[/tex] is False.
2. Analyze Statement B: [tex]\( c - k \leq 0 \)[/tex]
We need to determine whether [tex]\( c - k \leq 0 \)[/tex]. Since [tex]\( k \)[/tex] is negative and [tex]\( c \)[/tex] is positive, subtracting [tex]\( k \)[/tex] (a negative number) from [tex]\( c \)[/tex] (a positive number) essentially adds to [tex]\( c \)[/tex]:
[tex]\[ c - k = c + |k| > c \][/tex]
Given the result, [tex]\( c - k \leq 0 \)[/tex] is False.
3. Analyze Statement C: [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex]
This statement examines whether the square of the product of [tex]\( k \)[/tex] and [tex]\( c \)[/tex] is greater than or equal to the square root of [tex]\( c \)[/tex]:
[tex]\[ (k c)^2 = (k^2 \cdot c^2) \geq \sqrt{c} \][/tex]
Given the result, [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex] is True.
4. Analyze Statement D: [tex]\( k^2 \leq c^2 \)[/tex]
This statement evaluates if the square of [tex]\( k \)[/tex] is less than or equal to the square of [tex]\( c \)[/tex]:
[tex]\[ k^2 \leq c^2 \][/tex]
Given the result, [tex]\( k^2 \leq c^2 \)[/tex] is True.
Therefore, based on the analysis:
- Statement A is false.
- Statement B is false.
- Statement C is true.
- Statement D is true.
Conclusion:
The statements that must be true are:
- [tex]\( (k c)^2 \geq \sqrt{c} \)[/tex]
- [tex]\( k^2 \leq c^2 \)[/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.