Let’s break down and solve the problem step-by-step.
1. Initial Expression:
[tex]\[
[c(19+3) \times 8] \quad \xi+1+[7 \times 10-11] \times 5 \times 2
\][/tex]
2. Evaluate the Expression Inside the First Pair of Square Brackets:
[tex]\[
c(19+3) \times 8
\][/tex]
We assume [tex]\( c = 1 \)[/tex] (since the value of [tex]\( c \)[/tex] is not provided).
Therefore,
[tex]\[
1 \times (19 + 3) \times 8 = 1 \times 22 \times 8 = 176
\][/tex]
3. Evaluate the Expression Inside the Second Pair of Square Brackets:
[tex]\[
7 \times 10 - 11
\][/tex]
This simplifies to:
[tex]\[
70 - 11 = 59
\][/tex]
4. Compute the Entire Second Part of the Expression With the Adjustments:
[tex]\[
[59] \times 5 \times 2 + 1
\][/tex]
Breaking this down:
[tex]\[
59 \times 5 = 295
\][/tex]
Then,
[tex]\[
295 \times 2 = 590
\][/tex]
Adding 1 to this result:
[tex]\[
590 + 1 = 591
\][/tex]
5. Add the Results From the Two Separate Calculations:
- Result from the first expression: [tex]\( 176 \)[/tex]
- Result from the second expression: [tex]\( 591 \)[/tex]
Therefore, the final result is:
[tex]\[
176 + 591 = 767
\][/tex]
Summary:
- The value inside the first pair of square brackets is [tex]\( 176 \)[/tex].
- The value inside the second pair of square brackets, after all multiplications and additions, is [tex]\( 591 \)[/tex].
- The final result, adding these two parts, is [tex]\( 767 \)[/tex].
