Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Question 1 of 10

Before radar and sonar, sailors would climb to the top of their ships to watch for land or changes in weather. If the lookout at the top of the mast can see an island five miles away, about how tall is the mast? Round your answer to the nearest whole number if necessary. Use the formula for the relationship between height ([tex]h[/tex]) and visibility ([tex]d[/tex]):

[tex]
d=\frac{5}{6} \sqrt{h}
[tex]


Sagot :

To determine the height of the mast given that the lookout can see an island five miles away, we use the formula provided:

[tex]\[ d = \frac{5}{6} \sqrt{h} \][/tex]

where:
- [tex]\( d \)[/tex] is the distance the lookout can see (5 miles),
- [tex]\( h \)[/tex] is the height of the mast which we need to determine.

Here are the steps to find the height [tex]\( h \)[/tex]:

1. Substitute the given distance [tex]\( d \)[/tex] into the formula:

Since [tex]\( d = 5 \)[/tex] miles, we get:

[tex]\[ 5 = \frac{5}{6} \sqrt{h} \][/tex]

2. Solve for [tex]\( \sqrt{h} \)[/tex]:

To isolate [tex]\( \sqrt{h} \)[/tex], multiply both sides of the equation by [tex]\( \frac{6}{5} \)[/tex]:

[tex]\[ 5 \times \frac{6}{5} = \left( \frac{5}{6} \sqrt{h} \right) \times \frac{6}{5} \][/tex]

Simplifying the left side:

[tex]\[ 6 = \sqrt{h} \][/tex]

3. Solve for [tex]\( h \)[/tex]:

To find [tex]\( h \)[/tex], square both sides of the equation:

[tex]\[ (\sqrt{h})^2 = 6^2 \][/tex]

[tex]\[ h = 36 \][/tex]

4. Round to the nearest whole number if necessary:

In this case, [tex]\( h = 36 \)[/tex] is already a whole number.

Thus, the height of the mast is approximately 36 feet.