Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Final answer:
The answer involves calculating velocities and times for rocks dropped from a cliff. The initial and reached velocities are the same, and the time for the second rock in the air is determined.
Explanation:
a. To determine the speed at which the second rock was thrown, we can use the kinematic equation:
v = u + gt, where u is the initial velocity (0 m/s), g is the acceleration due to gravity (-9.81 m/s^2), and t is the time taken to reach the bottom (3.5 seconds). This gives us a velocity of 31.035 m/s.
b. When the first rock is reached by the second one, the velocity of the first rock is equal to the velocity of the second. Therefore, the velocity of the first rock when it was reached is 31.035 m/s.
c. For the time the second rock is in the air, we can consider either the time it takes to hit the bottom (3.5 seconds) or the total time both rocks are falling (4.5 seconds). So, the time for the second rock in the air is 3.5 seconds.
Learn more about Free Fall here:
https://brainly.com/question/37626569
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.