To determine the number of each type of atom in the compound ammonium sulfate, [tex]\((NH_4)_2SO_4\)[/tex], we need to break down its molecular structure and count the atoms systematically.
1. Counting Nitrogen (N) atoms:
- The ammonium ion is [tex]\((NH_4)^+\)[/tex].
- There are 2 ammonium ions in the formula [tex]\((NH_4)_2SO_4\)[/tex].
- Each [tex]\((NH_4)^+\)[/tex] contains 1 nitrogen atom.
- Therefore, the total number of nitrogen atoms = [tex]\(2 \times 1 = 2\)[/tex].
2. Counting Hydrogen (H) atoms:
- Each ammonium ion [tex]\((NH_4)^+\)[/tex] contains 4 hydrogen atoms.
- With 2 ammonium ions, the total number of hydrogen atoms = [tex]\(2 \times 4 = 8\)[/tex].
3. Counting Sulfur (S) atoms:
- There is 1 sulfate ion [tex]\((SO_4)^{2-}\)[/tex] in the formula.
- Each sulfate ion contains 1 sulfur atom.
- Therefore, the total number of sulfur atoms = [tex]\(1\)[/tex].
4. Counting Oxygen (O) atoms:
- Each sulfate ion [tex]\((SO_4)^{2-}\)[/tex] contains 4 oxygen atoms.
- Therefore, the total number of oxygen atoms = [tex]\(4\)[/tex].
Summarizing these findings in the table:
[tex]\[
\begin{tabular}{|c|c|}
\hline
atom & number in formula \\
\hline
nitrogen & 2 \\
\hline
hydrogen & 8 \\
\hline
sulfur & 1 \\
\hline
oxygen & 4 \\
\hline
\end{tabular}
\][/tex]
So, for the compound ammonium sulfate [tex]\((NH_4)_2SO_4\)[/tex], the number of each type of atom is as follows:
- Nitrogen: 2 atoms
- Hydrogen: 8 atoms
- Sulfur: 1 atom
- Oxygen: 4 atoms
