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Use the function below to find [tex][tex]$F(2)$[/tex][/tex].

[tex]
F(t) = 2 \cdot \frac{1}{2^{3t}}
[/tex]

A. [tex]\frac{1}{32}[/tex]
B. [tex]\frac{1}{64}[/tex]
C. [tex]\frac{1}{8}[/tex]
D. [tex]\frac{1}{16}[/tex]


Sagot :

To find [tex]\( F(2) \)[/tex] for the function [tex]\( F(t) = 2 \cdot \frac{1}{2^{3t}} \)[/tex], follow these steps:

1. Substitute [tex]\( t = 2 \)[/tex] into the function:
[tex]\[ F(2) = 2 \cdot \frac{1}{2^{3 \cdot 2}} \][/tex]

2. Simplify the exponentiation inside the function:
[tex]\[ 3 \cdot 2 = 6 \quad \text{so} \quad 2^{3 \cdot 2} = 2^6 \][/tex]

3. Calculate [tex]\( 2^6 \)[/tex]:
[tex]\[ 2^6 = 64 \][/tex]

4. Plug this result back into the function:
[tex]\[ F(2) = 2 \cdot \frac{1}{64} \][/tex]

5. Simplify the fraction:
[tex]\[ F(2) = \frac{2}{64} \][/tex]

6. Simplify the fraction further:
[tex]\[ \frac{2}{64} = \frac{1}{32} \][/tex]

So [tex]\( F(2) = \frac{1}{32} \)[/tex].

Thus, the correct answer is [tex]\( \boxed{\frac{1}{32}} \)[/tex].