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A diver dives [tex][tex]$17 \frac{2}{3}$[/tex][/tex] yards and then comes back to the surface. Then, she dives [tex][tex]$9 \frac{3}{8}$[/tex][/tex] yards deeper than her first dive. What is her depth, in yards, in relation to the surface of the water?

A. [tex]-27 \frac{7}{24}[/tex]
B. [tex]-27 \frac{1}{24}[/tex]
C. [tex]-8 \frac{7}{24}[/tex]
D. [tex]-8 \frac{1}{24}[/tex]


Sagot :

To find the diver's depth in relation to the surface of the water, let's break down the problem step-by-step:

1. Convert the mixed numbers to improper fractions:
- The initial dive is [tex]\(17 \frac{2}{3}\)[/tex] yards.
[tex]\[ 17 \frac{2}{3} = 17 + \frac{2}{3} = \frac{17 \times 3 + 2}{3} = \frac{51 + 2}{3} = \frac{53}{3} \text{ yards} \][/tex]

- The deeper dive is [tex]\(9 \frac{3}{8}\)[/tex] yards.
[tex]\[ 9 \frac{3}{8} = 9 + \frac{3}{8} = \frac{9 \times 8 + 3}{8} = \frac{72 + 3}{8} = \frac{75}{8} \text{ yards} \][/tex]

2. Sum the depths to find the total depth:
- The total depth is the sum of the two improper fractions. To sum these, we need a common denominator. The least common multiple (LCM) of the denominators 3 and 8 is 24.

- Convert each fraction to have the common denominator:
[tex]\[ \frac{53}{3} = \frac{53 \times 8}{3 \times 8} = \frac{424}{24} \][/tex]
[tex]\[ \frac{75}{8} = \frac{75 \times 3}{8 \times 3} = \frac{225}{24} \][/tex]

- Add the two fractions:
[tex]\[ \frac{424}{24} + \frac{225}{24} = \frac{424 + 225}{24} = \frac{649}{24} \][/tex]

3. Convert the improper fraction to a mixed number:
- Divide 649 by 24 to get the mixed number.
[tex]\[ 649 \div 24 \approx 27.041666666666668 \][/tex]

- This means:
[tex]\[ 649 = 27 \times 24 + 1 \quad (\text{as } 27 \times 24 = 648, \text{ with a remainder of 1}) \][/tex]
[tex]\[ \text{Thus, } \frac{649}{24} = 27 \frac{1}{24} \][/tex]

4. Determine the diver's depth in relation to the surface:
- Since the diver is below the surface, the total depth will be negative.
[tex]\[ -27 \frac{1}{24} \][/tex]

Therefore, the diver's depth in relation to the surface of the water is:
[tex]\[ -27 \frac{1}{24} \text{ yards} \][/tex]

This is the correct depth in relation to the surface of the water. Thus, the correct answer is:
[tex]\[ \boxed{-27 \frac{1}{24}} \][/tex]
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