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Write the following decimals in order of size, from smallest to largest:

3.2, 3.27, 3.72, 3.702, 3.02

Show your calculations and/or workings here:

Sagot :

To arrange the given decimals in order of size, from smallest to largest, let's compare their values step by step.

The given decimals are:
- 3.2
- 3.27
- 3.72
- 3.702
- 3.02

Step-by-step comparison:

1. 3.02 vs 3.2
- 3.02 is less than 3.2 because 02 is less than 20 in the hundredths place.

2. 3.02 vs 3.27
- 3.02 is less than 3.27 because 02 is less than 27 in the hundredths place.

3. 3.02 vs 3.72
- 3.02 is less than 3.72 because 02 is less than 72 in the hundredths place.

4. 3.02 vs 3.702
- 3.02 is less than 3.702 because 02 is less than 702 when comparing up to three decimal places.

Next, we know that 3.02 is the smallest number.

5. 3.2 vs 3.27
- 3.2 is less than 3.27 because 20 is less than 27 in the hundredths place.

6. 3.2 vs 3.72
- 3.2 is less than 3.72 because 20 is less than 72 in the hundredths place.

7. 3.2 vs 3.702
- 3.2 is less than 3.702 because comparing up to one decimal place, 2 is less than 7 when we consider the tenths place.

So next smallest number is 3.2.

8. 3.27 vs 3.72
- 3.27 is less than 3.72 because 27 is less than 72 in the hundredths place.

9. 3.27 vs 3.702
- 3.27 is less than 3.702 because comparing digit by digit in the hundredths place, 27 is less than 702.

This makes 3.27 the next smallest number.

10. 3.702 vs 3.72
- 3.702 is less than 3.72 because when we compare up to three decimal places, 702 is less than 720.

From the above comparisons, we find that the order of the decimals from smallest to largest is:

[tex]\[3.02, 3.2, 3.27, 3.702, 3.72\][/tex]

Therefore, writing the given decimals in order of size from smallest to largest we have:

[tex]\[3.02, 3.2, 3.27, 3.702, 3.72\][/tex]