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Two objects, mi and ma, have an elastic collision. The initial velocity of mi is +8.0 m/s and of m2 is -4.0 m/s. After the collision, the velocity of m, is +5.0m/s. What is the velocity of m2?
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After the collision, both momentum and kinetic energy are conserved in an elastic collision.
1. Calculate the total initial momentum of the system:
Initial momentum = mivi + mava
Initial momentum = mivi + mava = (mi 8.0) + (ma -4.0)
2. Calculate the total final momentum of the system:
Final momentum = mivf + mavf
Final momentum = mivf + mavf = (mi 5.0) + (ma vm2)
3. Since momentum is conserved, the initial momentum equals the final momentum:
mi8.0 + ma(-4.0) = mi5.0 + mavm2
4. Substitute the given values into the equation and solve for vm2:
mi8.0 + ma(-4.0) = mi5.0 + mavm2
8.0mi - 4.0ma = 5.0mi + vm2*ma
3.0mi = vm2*ma
vm2 = 3.0mi / ma
Therefore, the velocity of m2 (vm2) after the collision is 3.0 times the initial velocity of m1 (mi) divided by the mass of m2 (ma).
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