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Question 20 of 25

A school survey asked students which candidate they supported for class president. The survey data are shown in the relative frequency table.

\begin{tabular}{|c|c|c|c|}
\hline & Wilson & Martinez & Total \\
\hline Females & 0.24 & 0.30 & 0.54 \\
\hline Males & 0.18 & 0.28 & 0.46 \\
\hline Total & 0.42 & 0.58 & 1.0 \\
\hline
\end{tabular}

What percentage of males polled supported Wilson?

A. [tex]$46\%$[/tex]

B. [tex]$18\%$[/tex]

C. About [tex]$39\%$[/tex]

D. About [tex]$42\%$[/tex]

Sagot :

To determine the percentage of male students who supported Wilson, we need to consider the proportion of males who supported Wilson out of the total male students.

First, the given data tells us:
- The proportion of male students who supported Wilson is [tex]\(0.18\)[/tex].
- The total proportion of male students is [tex]\(0.46\)[/tex].

We calculate the percentage of males supporting Wilson by dividing the proportion of males supporting Wilson by the total proportion of male students, and then multiplying by 100 to convert it to a percentage:

[tex]\[ \text{Percentage of males supporting Wilson} = \left( \frac{0.18}{0.46} \right) \times 100 \][/tex]

By performing this calculation step by step, we find:

1. Divide [tex]\(0.18\)[/tex] by [tex]\(0.46\)[/tex]:

[tex]\[ 0.18 \div 0.46 \approx 0.3913 \][/tex]

2. Convert the result to a percentage by multiplying by 100:

[tex]\[ 0.3913 \times 100 \approx 39.13 \][/tex]

So, the percentage of males polled who supported Wilson is approximately [tex]\(39\%\)[/tex].

The correct answer is:
C. About [tex]\(39\%\)[/tex]