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Sagot :
To determine the phenotype ratio for the cross given in the Punnett square, let's analyze the genetic outcomes listed:
[tex]\[ \begin{array}{|c|c|c|} \hline & s & s \\ \hline s & SS & Ss \\ \hline s & Ss & ss \\ \hline \end{array} \][/tex]
Here are the possible combinations for the offspring:
1. SS
2. Ss
3. Ss
4. ss
Let's identify the phenotypes for each genotype:
- SS: Homogeneous dominant, resulting in short whiskers.
- Ss: Heterogeneous, resulting in short whiskers.
- Ss: Another heterogeneous, resulting in short whiskers.
- ss: Homogeneous recessive, resulting in long whiskers.
Now count the number of each phenotype:
- Short whiskers (SS, Ss, Ss): 3 times.
- Long whiskers (ss): 1 time.
Thus, the phenotype ratio for this cross is as follows:
- 3 short whiskers : 1 long whisker
So the correct answer is:
C. 3 short, 1 long
[tex]\[ \begin{array}{|c|c|c|} \hline & s & s \\ \hline s & SS & Ss \\ \hline s & Ss & ss \\ \hline \end{array} \][/tex]
Here are the possible combinations for the offspring:
1. SS
2. Ss
3. Ss
4. ss
Let's identify the phenotypes for each genotype:
- SS: Homogeneous dominant, resulting in short whiskers.
- Ss: Heterogeneous, resulting in short whiskers.
- Ss: Another heterogeneous, resulting in short whiskers.
- ss: Homogeneous recessive, resulting in long whiskers.
Now count the number of each phenotype:
- Short whiskers (SS, Ss, Ss): 3 times.
- Long whiskers (ss): 1 time.
Thus, the phenotype ratio for this cross is as follows:
- 3 short whiskers : 1 long whisker
So the correct answer is:
C. 3 short, 1 long
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