Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine the surface area of the smaller solid given the volumes and the surface area of the larger solid, we need to follow these steps:
1. Understand the relationship of similar solids:
- For similar solids, the ratio of their volumes is equal to the cube of the scale factor (k) between corresponding linear dimensions. That is:
[tex]\[ \left( \frac{\text{Volume of small solid}}{\text{Volume of large solid}} \right) = k^3 \][/tex]
2. Calculate the scale factor:
- Given that the volume of the smaller solid is [tex]\(210 \, \text{m}^3\)[/tex] and the volume of the larger solid is [tex]\(1680 \, \text{m}^3\)[/tex]:
[tex]\[ \left( \frac{210}{1680} \right) = k^3 \][/tex]
- Simplifying the fraction, we get:
[tex]\[ \frac{210}{1680} = \frac{1}{8} = \frac{1}{2^3} = (0.5)^3 \][/tex]
- Therefore, the scale factor [tex]\(k\)[/tex] is:
[tex]\[ k = 0.5 \][/tex]
3. Relate the surface areas of the similar solids:
- The ratio of their surface areas is equal to the square of the scale factor. That is:
[tex]\[ \left( \frac{\text{Surface Area of small solid}}{\text{Surface Area of large solid}} \right) = k^2 \][/tex]
4. Calculate the surface area of the smaller solid:
- Given that the surface area of the larger solid is [tex]\(856 \, \text{m}^2\)[/tex]:
[tex]\[ \left( \frac{\text{Surface Area of small solid}}{856} \right) = (0.5)^2 \][/tex]
- Calculating [tex]\( (0.5)^2 \)[/tex], we get:
[tex]\[ (0.5)^2 = 0.25 \][/tex]
- Thus:
[tex]\[ \text{Surface Area of small solid} = 0.25 \times 856 \, \text{m}^2 \][/tex]
- Performing the multiplication:
[tex]\[ 0.25 \times 856 = 214 \, \text{m}^2 \][/tex]
Therefore, the surface area of the smaller solid is:
[tex]\[ \boxed{214 \, \text{m}^2} \][/tex]
1. Understand the relationship of similar solids:
- For similar solids, the ratio of their volumes is equal to the cube of the scale factor (k) between corresponding linear dimensions. That is:
[tex]\[ \left( \frac{\text{Volume of small solid}}{\text{Volume of large solid}} \right) = k^3 \][/tex]
2. Calculate the scale factor:
- Given that the volume of the smaller solid is [tex]\(210 \, \text{m}^3\)[/tex] and the volume of the larger solid is [tex]\(1680 \, \text{m}^3\)[/tex]:
[tex]\[ \left( \frac{210}{1680} \right) = k^3 \][/tex]
- Simplifying the fraction, we get:
[tex]\[ \frac{210}{1680} = \frac{1}{8} = \frac{1}{2^3} = (0.5)^3 \][/tex]
- Therefore, the scale factor [tex]\(k\)[/tex] is:
[tex]\[ k = 0.5 \][/tex]
3. Relate the surface areas of the similar solids:
- The ratio of their surface areas is equal to the square of the scale factor. That is:
[tex]\[ \left( \frac{\text{Surface Area of small solid}}{\text{Surface Area of large solid}} \right) = k^2 \][/tex]
4. Calculate the surface area of the smaller solid:
- Given that the surface area of the larger solid is [tex]\(856 \, \text{m}^2\)[/tex]:
[tex]\[ \left( \frac{\text{Surface Area of small solid}}{856} \right) = (0.5)^2 \][/tex]
- Calculating [tex]\( (0.5)^2 \)[/tex], we get:
[tex]\[ (0.5)^2 = 0.25 \][/tex]
- Thus:
[tex]\[ \text{Surface Area of small solid} = 0.25 \times 856 \, \text{m}^2 \][/tex]
- Performing the multiplication:
[tex]\[ 0.25 \times 856 = 214 \, \text{m}^2 \][/tex]
Therefore, the surface area of the smaller solid is:
[tex]\[ \boxed{214 \, \text{m}^2} \][/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.