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Find the [tex]$y$[/tex]-intercept.

[tex]\[ y = \frac{3x - 6}{x + 2} \][/tex]

[tex]\[ (0, [?]) \][/tex]

Hint: Where does the graph cross the [tex]$y$[/tex]-axis? What does [tex]$y$[/tex] equal when [tex]$x = 0$[/tex]?

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GinnyAnswer
To find the [tex]\( y \)[/tex]-intercept of the function, we need to determine the value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex]. The [tex]\( y \)[/tex]-intercept is the point where the graph of the function crosses the [tex]\( y \)[/tex]-axis.

Given the function:
[tex]\[ y = \frac{3x - 6}{x + 2} \][/tex]

We substitute [tex]\( x = 0 \)[/tex] into the equation to find the [tex]\( y \)[/tex]-intercept:
[tex]\[ y = \frac{3(0) - 6}{0 + 2} \][/tex]

Simplify the expression inside the equation:
[tex]\[ y = \frac{0 - 6}{2} \][/tex]
[tex]\[ y = \frac{-6}{2} \][/tex]
[tex]\[ y = -3 \][/tex]

Thus, the [tex]\( y \)[/tex]-intercept is:
[tex]\[ (0, -3) \][/tex]

The value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex] is [tex]\(-3\)[/tex]. Therefore, the graph crosses the [tex]\( y \)[/tex]-axis at the point [tex]\((0, -3)\)[/tex].
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