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What is the momentum of a [tex][tex]$15 \, \text{kg}$[/tex][/tex] tire rolling down a hill at [tex][tex]$3 \, \text{m/s}$[/tex][/tex]?

A. [tex][tex]$5 \, \text{kg} \cdot \text{m/s}$[/tex][/tex]
B. [tex][tex]$18 \, \text{kg} \cdot \text{m/s}$[/tex][/tex]
C. [tex][tex]$45 \, \text{kg} \cdot \text{m/s}$[/tex][/tex]
D. [tex][tex]$60 \, \text{kg} \cdot \text{m/s}$[/tex][/tex]


Sagot :

To find the momentum of a tire, we need to use the formula for momentum, which is:

[tex]\[ \text{Momentum} = \text{mass} \times \text{velocity} \][/tex]

Given the values:
- Mass ([tex]\( m \)[/tex]) = 15 kg
- Velocity ([tex]\( v \)[/tex]) = 3 m/s

We can plug these values into the formula:

[tex]\[ \text{Momentum} = 15 \, \text{kg} \times 3 \, \text{m/s} \][/tex]

Performing the multiplication:

[tex]\[ \text{Momentum} = 45 \, \text{kg} \cdot \text{m/s} \][/tex]

Therefore, the momentum of the 15 kg tire rolling down the hill at 3 m/s is:

[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]

So, the correct answer is:

[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]