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Sagot :
To find the momentum of a tire, we need to use the formula for momentum, which is:
[tex]\[ \text{Momentum} = \text{mass} \times \text{velocity} \][/tex]
Given the values:
- Mass ([tex]\( m \)[/tex]) = 15 kg
- Velocity ([tex]\( v \)[/tex]) = 3 m/s
We can plug these values into the formula:
[tex]\[ \text{Momentum} = 15 \, \text{kg} \times 3 \, \text{m/s} \][/tex]
Performing the multiplication:
[tex]\[ \text{Momentum} = 45 \, \text{kg} \cdot \text{m/s} \][/tex]
Therefore, the momentum of the 15 kg tire rolling down the hill at 3 m/s is:
[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]
So, the correct answer is:
[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]
[tex]\[ \text{Momentum} = \text{mass} \times \text{velocity} \][/tex]
Given the values:
- Mass ([tex]\( m \)[/tex]) = 15 kg
- Velocity ([tex]\( v \)[/tex]) = 3 m/s
We can plug these values into the formula:
[tex]\[ \text{Momentum} = 15 \, \text{kg} \times 3 \, \text{m/s} \][/tex]
Performing the multiplication:
[tex]\[ \text{Momentum} = 45 \, \text{kg} \cdot \text{m/s} \][/tex]
Therefore, the momentum of the 15 kg tire rolling down the hill at 3 m/s is:
[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]
So, the correct answer is:
[tex]\[ 45 \, \text{kg} \cdot \text{m/s} \][/tex]
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