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If [tex][tex]$f\left(\frac{3x-1}{2}\right) = 6x + 1$[/tex][/tex], then find the value of [tex][tex]$f(2)$[/tex][/tex].

Sagot :

To solve the given problem [tex]\( f\left(\frac{3 x-1}{2}\right)=6 x+1 \)[/tex] and find the value of [tex]\( f(2) \)[/tex], we can follow these steps:

1. Set the expression inside the function equal to 2:
[tex]\[ \frac{3x - 1}{2} = 2 \][/tex]

2. Solve for [tex]\(x\)[/tex]:
- First, multiply both sides of the equation by 2 to clear the fraction:
[tex]\[ 3x - 1 = 4 \][/tex]
- Next, add 1 to both sides to isolate the [tex]\(3x\)[/tex] term:
[tex]\[ 3x = 5 \][/tex]
- Now, divide both sides by 3 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{5}{3} \][/tex]

3. Substitute [tex]\(x = \frac{5}{3}\)[/tex] back into the function [tex]\(f\left(\frac{3 x-1}{2}\right)=6 x+1\)[/tex] to find [tex]\( f(2) \)[/tex]:
- The given function can be rewritten with [tex]\(x = \frac{5}{3}\)[/tex]:
[tex]\[ f\left(2\right) = 6 \left(\frac{5}{3}\right) + 1 \][/tex]
- Simplify inside the parenthesis:
[tex]\[ f(2) = 2 \times 5 + 1 \][/tex]
[tex]\[ f(2) = 10 + 1 \][/tex]
[tex]\[ f(2) = 11 \][/tex]

Hence, the value of [tex]\( f(2) \)[/tex] is [tex]\( 11 \)[/tex].