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A retail store offers all television sets at 80% (or [tex]\(\frac{80}{100}\)[/tex]) of their original price if the customer buys a store membership for \[tex]$100. If \(p\) is the price of a television set, which expression represents the amount that a new customer will have to pay to get the discount? How much will a \$[/tex]1,500 television cost (including the membership fee) if the customer gets the discounted price?

A. The expression is [tex]\(\left(p \times \frac{80}{100}\right) - 100\)[/tex], and the cost is \[tex]$1,100.
B. The expression is \(\left(p \times \frac{80}{100}\right)\), and the cost is \$[/tex]1,200.
C. The expression is [tex]\(\left(p \times \frac{80}{100}\right) + 100\)[/tex], and the cost is \[tex]$1,300.
D. The expression is \(p - 100\), and the cost is \$[/tex]1,400.

Sagot :

To determine the correct answer, let's break down the problem step-by-step.

1. Identify the original price of the television:
- The original price of the television is given by [tex]\( p \)[/tex].
- In this scenario, [tex]\( p = \$1,500 \)[/tex].

2. Discount offered:
- The television is sold at [tex]\( 80\% \)[/tex] of its original price.
- [tex]\( 80\% \)[/tex] can be expressed as [tex]\( \frac{80}{100} \)[/tex].

3. Calculate the discounted price of the television:
- To find the discounted price, multiply the original price [tex]\( p \)[/tex] by [tex]\( \frac{80}{100} \)[/tex].
- [tex]\[ \text{Discounted Price} = p \times \frac{80}{100} \][/tex]

4. Membership fee:
- To get the discounted price, the customer has to buy a store membership which costs [tex]\( \$100 \)[/tex].

5. Calculate the total cost including the membership fee:
- Add the membership fee to the discounted price.
- [tex]\[ \text{Total Cost} = \left(p \times \frac{80}{100}\right) + 100 \][/tex]

Let's apply these steps to find out how much a [tex]$1,500 television will cost including the membership fee: 1. Original price (\( p \)): - \( p = \$[/tex]1,500 \).

2. Calculate the discounted price:
- [tex]\[ \text{Discounted Price} = 1500 \times \frac{80}{100} = 1500 \times 0.80 = 1200 \][/tex]

3. Add the membership fee:
- [tex]\[ \text{Total Cost} = 1200 + 100 = 1300 \][/tex]

So, the complete expression representing the amount that a new customer will have to pay is:

[tex]\[ \left(p \times \frac{80}{100}\right) + 100 \][/tex]

And for a [tex]$1,500 television, the total cost, including the membership fee, would be $[/tex]1,300.

Therefore, the correct answer is:
C. The expression is [tex]\(\left(p \times \frac{80}{100}\right)+100\)[/tex], and the cost is \$1,300.