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I need y=(x-3)(x+1) in standard form

Sagot :

Hi1315

Answer:

y = x² - 2x - 3

Step-by-step explanation:

The standard form of a quadratic equation is  y = ax² + bx + c .

Here are the steps:

1. Expand the expression  (x - 3)(x + 1) :

  y = (x - 3)(x + 1)

2. Use the distributive property to expand the product:

  y = x(x + 1) - 3(x + 1)

3. Distribute  x  and  -3 :

  y = x² + x - 3x - 3

4. Combine like terms:

  y = x² - 2x - 3

So, the standard form of the equation  y = (x - 3)(x + 1)  is:

y = x² - 2x - 3

Answer:

[tex]y=x^2-2x-3[/tex]

Step-by-step explanation:

Standard Form

Standard form for a quadratic equation is always in this format,

[tex]y=ax^2+bx+c[/tex].

The usual way of transforming a quadratic from its vertex or factored form to standard form is by expanding and simplifying the equation at hand.

[tex]\hrulefill[/tex]

Solving the Problem

We can expand this factored form using the FOIL method or summing the products of the,

  • first terms
  • outer terms
  • inner terms
  • last terms

with respective to each factor.

Doing that we get,

                                  [tex]y=x^2+x-3x-3[/tex]

                                      [tex]y=x^2-2x-3[/tex].

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